20%, because if 65 is 100, then 52 is 80% out of 65; so 100 - 80 is 20
Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.
They put some red and blue power chips and draw each one. If same colour, Aaron will wash and if not same colours Erica will wash
If the game is to be fair, then both should have equal chances of opportunity for washing.
i.e. Probability for Erica washing = Prob of Aaron washing
i.e. P(different chips) = P(same colour chips)
Say there are m red colours and n blue colours.
Both are drawing at the same time.
Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2
Probfor different colour = mC1+nC1/(m+n)C2
The two would be equal is mC2 +nC2 = m+n
This is possible if mC2 =m and nC2 = n.
Or m = 2+1 =3 and n =3
That for a fair game we must have both colours to be 3.
First of all, you want the variable to be isolated, so in order to do that, you divide in both sides. Ten divided by two is five. So f = 5.
2f + 10
--- ---
2 2
10 divided by 2 = 5
The probability that Jenny gets to choose lunch is 64% 0.64 (rounded) or 0.636.
Work:
Number of roses and carnations divided by the total number of flowers
<span>7/11 = 0.636 = 0.64 (rounded)
once again same answer
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Y = √8x³
dy/dt = 2√2 * 3/2 * √x * dx/dt
⇒ 5 = 2√2 * 3/2 * √2 * dx/dt
⇒ 5 = 6 dx/dt
⇒dx/dt = 5/6 cm/s
x coordinate is changing at 5/6 cm/s
Hope it helps!
