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Masteriza [31]
3 years ago
9

Brian, a landscape architect, submitted a bid on each of three home landscaping projects. He estimates that the probabilities of

winning the bid on Project A, Project B, and Project C are 0.8, 0.5, and 0.2, respectively. Assume that the probability of winning a bid on one of the three projects is independent of winning or losing the bids on the other two projects. Find the probability that Brian will experience the following. (a) Win all three of the bids (b) Win exactly two of the bids
Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:

a:  0.08, or 8% chance he wins all 3

b:  0.42, or 42% chance he wins 2

Step-by-step explanation:

P(win A) = 0.8

P(lose A) = 0.2

P(win B) = 0.5

P(lose B) = 0.5

P(win C) = 0.2

P(lose C) = 0.8

The situations are independent, so we multiply probabilities together.

To win all 3:  P(win A)*P(win B)*P(win C) = 0.8*0.5*.02 = 0.08

To win 2 of the 3 there are 3 ways to do this.  We add up the probabilities of the 3 situations...

P(win A)*P(win B)*(lose C) = 0.8*0.5*0.8 = 0.32

P(win A)*P(lose B)*P(win C) = 0.8*0.5*0.2 = 0.08

P(lose A)*P(win B)*P(win C) = 0.2*0.5*.02 = 0.02

0.32 + 0.08 + 0.02 = 0.42

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Answer:

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Step-by-step explanation:

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Since the angles of 5x + 4 and the one adjacent to x = 14 are corresponding angles, they are equal. That means that (5x + 4) + (x + 14) = 180 degrees.

5x + 4 + x + 14 = 180

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Also, the angle (5x + 4) and (2y - 9) are vertical angles, they are equal in value. We know the value of x now, so we'll substitute that in and solve for y.

5(27) + 4 = 2y - 9

135 + 4 = 2y - 9

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Step-by-step explanation:

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