3 years ago

2 5/5+7 2/5= Adding mixed numbers

Mathematics

2 answers:

soldier1979 [14.2K]3 years ago

5 0

Hey there!

$\bold{2\frac{5}{5}+7\frac{2}{5}}$

$\bold{2\frac{2}{5}=21}$
$\bold{21+7\frac{2}{5}}$
$\bold{7\frac{2}{5}=\frac{37}{5}}$
$\bold{3+\frac{37}{5}}$
$\boxed{\boxed{\bold{Answer: \frac{52}{5} or10\frac{2}{5}}}}$

Good luck on your assignment and enjoy your day!

~ $\bold{LoveYourselfFirst:)}$

Sidana [21]3 years ago

4 0

I don't know if this answer is right but I think it would be 52

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dusya [7]

Answer:

$\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}$

Step-by-step explanation:

$\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}$