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OleMash [197]
3 years ago
13

Please I need answer fast will give brainliest

Mathematics
1 answer:
Sonbull [250]3 years ago
6 0
Point slope is y-y1=m(x-x1)
Keep y and x as they are (do not plug anything in for those).
Variable m is the slope.
x1 and y1 are part of the point, which is in (x, y) form.
With the information given, plug each into the equation.
m= 2 (It's the slope)
x1=-8
y1=5
Put these variables into the equation like this-
y-5=2(x--8)
The two negatives cancel out (between x and 8) so your final answer is-
y-5=2(x+8)
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If (k,6k) and (3k,10k) are two points on the graph of a line and K is not equal to 0, what is the slope of the line?
Nataliya [291]

Answer:

Step-by-step explanation:

slope = y2-y1/x2-x1

Given the coordinates (k,6k) and (3k,10k)

x1 = k

y1 = 6k

x2 = 3k

y2 = 10k

Substitute

slope = 10k-6k/3k-k

slopw = 4k/2k

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Hence the slope of the line is 2

7 0
3 years ago
Consider M, N, and P. collinear points on MP.
Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}

2. Point N lies to the right from point P, then MP + PN = MN.  Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}

3 0
3 years ago
I will give you the brainliest if you answer asap please
IRINA_888 [86]

Answer:

168

Step-by-step explanation:

You just need to triple the answer to get 168.

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The sum of two numbers is 17 and the sum of their square is 145. find the larger number.
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The larger number is 9.
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Talja [164]
When the squared terms are of different signs, the equation generally describes a hyperbola. This one has its vertices at x=±30, so the parameters of interest are
  domain: (-∞, -30] ∪ [30, ∞)
  range: (-∞, ∞)

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4 years ago
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