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SIZIF [17.4K]
3 years ago
8

Matt and Jim, working together, can weed the garden in 10 hours. Working alone, Jim takes five times as long as Matt. How long d

oes it take Matt to weed the garden alone?
Mathematics
2 answers:
asambeis [7]3 years ago
8 0

Answer:

1.67hrs

Step-by-step explanation:

Let the time taken by Matt to weed the farm be x and that of Jim be y

When they both work together

x + y = 10

Working alone Jim takes as long as 5 times Matt .

That’s y = 5x

Substitute 5x for y in the first equation

That’s x + 5x = 10

6x = 10

Divide both sides by 6

6x/6 = 10/6

x = 1.67 hrs

It takes Matt 1.67hrs to weed the farm alone

Harlamova29_29 [7]3 years ago
6 0

Answer:

10x5=50 Hours!

Step-by-step explanation:

All you just got to do is <u>10x5</u> DUH Easy!

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K is the midpoint of VW.<br> If KV = 3x and KW = 5x-10, what is VW?<br> 22.5<br> 15<br> 7.5<br> 30
LekaFEV [45]

Answer:

15

Step-by-step explanation:

just took the test. x=5 and the answer to the equation is 15

5 0
3 years ago
I don't know how to do this or what i'm doing plz help
mote1985 [20]

recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

7 0
3 years ago
Jason and Kyle both choose a number from 1 to 10 at random. What is the probability that both numbers are odd?
Artemon [7]
Your answer is 

B) 1/2

because there are 5 odd and 5 even numbers from 5 through 10, so it would be 1/2.

Glad I could help, and good luck!


4 0
3 years ago
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The pH of a substance added to a citrate buffer, y, depending on the ratio of citric acid to sodium citrate, x, can be modeled u
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Answer:

Yes it's A. 0.79

Step-by-step explanation:

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Nat2105 [25]

Answer:

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