Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.

At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Answer:
53.1 degrees
Step-by-step explanation:
use sohcahtoa
sin(x) = 12/15
sin(x) = 0.8
sin-1(0.8) = 53.1301
Answer:
No i dont think so but im not sure
Step-by-step explanation:
Hey there!
Okay let's get cracking :D
The equation is.... (2x/3) - 6 = 9
2x/3 = 15
2x = 45
<u>x = 22.5</u><u /> <----- And that is your answer!
I hope it helped!
<u>Please vote for me as Brainliest if there is a second answer!</u>