1 pound = 16 ounces
5 < 16
5 ounces < 16 ounces
5 ounces < 1 pound
1 pound is greater
Answer:
Step-by-step explanation:
i go to southwind what’s the answer ??
Given:
DE = (6x - 9) cm
EF = (4x + 4) cm
LM = 14 cm
MN = 16 cm
To find:
The value of x.
Solution:
<em>If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.</em>
![$\Rightarrow \frac{DE}{EF} =\frac{LM}{MN}](https://tex.z-dn.net/?f=%24%5CRightarrow%20%5Cfrac%7BDE%7D%7BEF%7D%20%3D%5Cfrac%7BLM%7D%7BMN%7D)
![$\Rightarrow \frac{6x-9}{4x+4} =\frac{14}{16}](https://tex.z-dn.net/?f=%24%5CRightarrow%20%5Cfrac%7B6x-9%7D%7B4x%2B4%7D%20%3D%5Cfrac%7B14%7D%7B16%7D)
Do cross multiplication.
![$\Rightarrow 16( {6x-9})=14 ({4x+4} )](https://tex.z-dn.net/?f=%24%5CRightarrow%2016%28%20%7B6x-9%7D%29%3D14%20%28%7B4x%2B4%7D%20%29)
![$\Rightarrow 96x-144=56 x+56](https://tex.z-dn.net/?f=%24%5CRightarrow%2096x-144%3D56%20x%2B56)
Add 144 on both sides.
![$\Rightarrow 96x-144+144=56 x+56+144](https://tex.z-dn.net/?f=%24%5CRightarrow%2096x-144%2B144%3D56%20x%2B56%2B144)
![$\Rightarrow 96x=56 x+200](https://tex.z-dn.net/?f=%24%5CRightarrow%2096x%3D56%20x%2B200)
Subtract 56x from both sides.
![$\Rightarrow 96x-56x=56 x+200-56x](https://tex.z-dn.net/?f=%24%5CRightarrow%2096x-56x%3D56%20x%2B200-56x)
![$\Rightarrow 40x=200](https://tex.z-dn.net/?f=%24%5CRightarrow%2040x%3D200)
Divide by 40 on both sides, we get
![$\Rightarrow x=5](https://tex.z-dn.net/?f=%24%5CRightarrow%20x%3D5)
The value of x is 5.
Answer:
![v_{o} \approx 31.247\,mph](https://tex.z-dn.net/?f=v_%7Bo%7D%20%5Capprox%2031.247%5C%2Cmph)
Step-by-step explanation:
The deceleration experimented by the car is the product of kinetic coefficient of friction and gravitational constant:
![a = \mu_{k}\cdot g](https://tex.z-dn.net/?f=a%20%3D%20%5Cmu_%7Bk%7D%5Ccdot%20g)
![a = (1.02)\cdot \left(32.174\,\frac{ft}{s^{2}} \right)](https://tex.z-dn.net/?f=a%20%3D%20%281.02%29%5Ccdot%20%5Cleft%2832.174%5C%2C%5Cfrac%7Bft%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29)
![a = 32.817\,\frac{ft}{s^{2}}](https://tex.z-dn.net/?f=a%20%3D%2032.817%5C%2C%5Cfrac%7Bft%7D%7Bs%5E%7B2%7D%7D)
The initial speed is computed from the following kinematic expression:
![v^{2} = v_{o}^{2} - 2\cdot a \cdot \Delta s](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%20v_%7Bo%7D%5E%7B2%7D%20-%202%5Ccdot%20a%20%5Ccdot%20%5CDelta%20s)
![v_{o} = \sqrt{v^{2}+2\cdot a\cdot \Delta s}](https://tex.z-dn.net/?f=v_%7Bo%7D%20%3D%20%5Csqrt%7Bv%5E%7B2%7D%2B2%5Ccdot%20a%5Ccdot%20%5CDelta%20s%7D)
![v_{o} = \sqrt{\left(0\,\frac{ft}{s} \right)^{2}+2\cdot \left(32.817\,\frac{ft}{s^{2}} \right)\cdot (32\,ft)}](https://tex.z-dn.net/?f=v_%7Bo%7D%20%3D%20%5Csqrt%7B%5Cleft%280%5C%2C%5Cfrac%7Bft%7D%7Bs%7D%20%5Cright%29%5E%7B2%7D%2B2%5Ccdot%20%5Cleft%2832.817%5C%2C%5Cfrac%7Bft%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%2832%5C%2Cft%29%7D)
![v_{o}\approx 45.829\,\frac{ft}{s}](https://tex.z-dn.net/?f=v_%7Bo%7D%5Capprox%2045.829%5C%2C%5Cfrac%7Bft%7D%7Bs%7D)
![v_{o} \approx 31.247\,mph](https://tex.z-dn.net/?f=v_%7Bo%7D%20%5Capprox%2031.247%5C%2Cmph)
Answer:
its probably division property if equality
Step-by-step explanation:
because it has division in it