URGENT!!! Simplify the expression with steps
1 answer:
Hello :)
The first thing you want to do is use foil
F- first O- outer I-inner L-last
Lets start with F ( first)
6 × 3 = 18
Now, lets do O (outer)
6 × 2√10 = 12√10
<em>how to do it ?</em>
(6×2=12 and keep √10)
Then, we are going to do I ( inner)
(-√5) × 3= -3√5
<em>how to do it ?</em>
remove the parenthesis
-√5 × 3= -3√5
Lastly, we are going to do L (last)
(-√5) × 2 √10= -10√2
<em>how to do it ?</em>
remove the parenthesis from (-√5), then factor 2 √10
-√5 × 2
-√5 × 2 √5√2
there are two 5's so we use our radical rule √a√a=a
-2 × 5√2=-10√2
The last thing you have to do is put them all together
18+12√20-3√5-10√2
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Answer: see attachment
<u>Step-by-step explanation:</u>
The standard form of a linear equation is: Ax + By = C
where A, B, and C are INTEGERS.
The 1st, 3rd, & 4th equations are in the form Ax + By = C
The 2nd, 5th, & 6th equations are NOT in standard form.
Answer:
P ( 1.2 < X < 2.1 ) = 0.3
Step-by-step explanation:
Given:
Uniform distribution over interval (0,3) can be modeled by a probability density function f(x)
f(x) = 1 / (b - a)
Where a < x < b is the domain at which function is defined:
f(x) = 1 / (3) = 1 / 3
Where, X - U ( u , δ )
u = ( a + b ) / 2 = (0 +3) / 2 = 1.5
δ = ( b - a ) / sqrt (12) = (3 - 0) / sqrt (12) = 0.866
Hence,
X - U ( 1.5 , 0.866 )
There-fore calculating P ( 1.2 < X < 2.1 ):
Where, a = 1.2 and b = 2.1
P ( 1.2 < X < 2.1 ) = x / 3 |
P ( 1.2 < X < 2.1 ) = 2.1 /3 - 1.2 / 3 = 0.3
Answer: P ( 1.2 < X < 2.1 ) = 0.3