The final result is: x = 4, 3.
URGENT!!! Simplify the expression with steps
1 answer:
Hello :)
The first thing you want to do is use foil
F- first O- outer I-inner L-last
Lets start with F ( first)
6 × 3 = 18
Now, lets do O (outer)
6 × 2√10 = 12√10
<em>how to do it ?</em>
(6×2=12 and keep √10)
Then, we are going to do I ( inner)
(-√5) × 3= -3√5
<em>how to do it ?</em>
remove the parenthesis
-√5 × 3= -3√5
Lastly, we are going to do L (last)
(-√5) × 2 √10= -10√2
<em>how to do it ?</em>
remove the parenthesis from (-√5), then factor 2 √10
-√5 × 2
-√5 × 2 √5√2
there are two 5's so we use our radical rule √a√a=a
-2 × 5√2=-10√2
The last thing you have to do is put them all together
18+12√20-3√5-10√2
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The final result is: x = 4, 3.
‣ A coin is tossed three times.
‣ The probability of getting,
1) Exactly 3 tails
2) At most 2 heads
3) At least 2 tails
4) Exactly 2 heads
5) Exactly 3 heads
★ When three coins are tossed,
then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}
[here H denotes head and T denotes tail]
⇒Total number of outcomes = 8
<u>1) Exactly 3 tails </u>
Here
• Favourable outcomes = {HHH} = 1
• Total outcomes = 8
<u>2) At most 2 heads</u>
[It means there can be two or one or no heads]
Here
• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7
• Total outcomes = 8
<u>3) At least 2 tails </u>
[It means there can be two or more tails]
Here
• Favourable outcomes = {TTH, TTT, HTT, THT} = 4
• Total outcomes = 8
<u>4) Exactly 2 heads </u>
Here
• Favourable outcomes = {HTH, THH, HHT } = 3
• Total outcomes = 8
<u>5) Exactly 3 heads</u>
Here
• Favourable outcomes = {HHH} = 1
• Total outcomes = 8