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Maurinko [17]
2 years ago
9

Adding fractions 5 over 10 + 1 over 3

Mathematics
2 answers:
Ray Of Light [21]2 years ago
7 0

Answer:

25/30

Simplified: 5/6

Step-by-step explanation:

Have a good day!

Please rate and mark brainliest!

Blizzard [7]2 years ago
6 0

Answer:

the answer is 25/30 or in a simple form 5/6

Step-by-step explanation:

You might be interested in
Simplify the following expression.
Blababa [14]

Answer:

-6x

Step-by-step explanation:

I just answered this

it will equal -6x

good luck :)

5 0
3 years ago
Match each equation to its equivalent equation in slope-intercept form.
Bumek [7]
1.) y+6=3(x+2)    C
     y+6=3x+6
     y=3x+6-6
     y=3x+6
2.) y=1/2(x+8)-2    B
     y=1/2x+4-2
     y=1/2x+2
3.) y+1=1(x-3)    E
     y+1=x-3
     y=x-3-1
     y=x-4
4.) -4x+y=-2    A
     y=-4x-2
5.) 2x-4y=-4     F
     -4y=-2x-4
     y=-2/-4x-4/-4
     y=2/4x+4/4
     y=1/2x+1
6.) 2x+4y=8     D
     4y=-2x+8
     y=-2/4x+8/4
     y=-1/2x+4/2
     y=-1/2x+2
6 0
3 years ago
Select the equivalent expressions for z divided by 144
Ivahew [28]

Answer:

A: 144/z

Step-by-step explanation:

Hopefully this helps!

4 0
3 years ago
Chart:
True [87]
I would say B because it only makes since, colleges are looking for whats better in students and you will also work in groups also. So i would go with B :)
5 0
3 years ago
A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

5 0
3 years ago
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