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3 years ago

Which triangle is a right triangle?

Mathematics

1 answer:

iren [92.7K]3 years ago

4 0

Answer:

A right triangle is always 90 degrees.

Step-by-step explanation:

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the owner of an aquatic store used 17 1/2 gallons of water to fill aquariums. he puts 5 5/6 gallons of water in each aquarium. h

BabaBlast [244]

I have absolutely no idea. sorry that i didn’t answer but thanks for the second answer that i needed to ask my question. i’m stupid do i have no idea what it’s asking. sorry

6 0

3 years ago

(PLEASE ANSWER + 10 POINTS!!)

Burka [1]

A^2 + b^2 = c^2

297^2 + 394^2 = C^2

88209+155236=243445

take the square root of 243445

you get 493.4

which in your answer they're rounded

so your answer is

C. 493

3 0

4 years ago

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In a city, the distance between the library and the police station is 3 miles less than twice the distance between the police st

insens350 [35]

5 - 3= 2 x 2

4 miles

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4 years ago

Drag the tiles to the boxes to form correct pairs

Brums [2.3K]

Answer:

1) $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2) $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3) $tan^{-1}(\sqrt{3})=60$

4) $sin^{-1}(1)=90$

Step-by-step explanation:

1) Value of $sin^{-1}(\frac{\sqrt{2} }{2}) =sin^{-1}(\frac{1}{\sqrt{2} })$

since sin45° = 1/√2

Therefore $sin^{-1}(\frac{1}{\sqrt{2} })=45$

2).Value of $cos^{-1}(\frac{\sqrt{3} }{2})$

Since cos 30° = √3/2

Therefore $cos^{-1}(\frac{\sqrt{3} }{2})=30$

3). Value of $tan^{-1}(\frac{3}{\sqrt{3} }) = tan^{-1}(\sqrt{3})=60$

since tan 60° = √3

therefore $tan^{-1}(\sqrt{3})=60$

4). Value of $sin^{-1}(1)$

Since sin90°=1

Therefore $sin^{-1}(1)=90$

3 0

3 years ago

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Which is the factorization of 8x2 13x – 6? (8x – 3)(x 2) (x – 6)(8x 1) (2x – 2)(4x 3) (4x – 1)(2x 6)

vagabundo [1.1K]

we have

$8x^2+13x - 6$

Equate the function to zero

$8x^2+13x - 6=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$8x^2+13x = 6$

Factor the leading coefficient

$8(x^2+\frac{13}{8}x) = 6$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$8(x^2+\frac{13}{8}x) = 6$

$8(x^2+\frac{13}{8}x+\frac{169}{256}) = 6 +\frac{169}{32} \\ \\ 8(x+\frac{13}{16} )^{2} =\frac{361}{32} \\ \\ (x+\frac{13}{16} )^{2} =\frac{361}{256}\\ \\ (x+\frac{13}{16} ) =(+/-)\sqrt{\frac{361}{256}} \\ \\ (x+\frac{13}{16} ) =(+/-)\frac{19}{16} \\ \\ x1=-\frac{13}{16} +\frac{19}{16} =\frac{6}{16}\\ \\ x2=-\frac{13}{16} -\frac{19}{16}=-2$

the factorization is equal to

$8*(x-\frac{6}{16} )*(x+2)=(8x-3)*(x+2)$

therefore

<u>the answer is</u>

$(8x-3)*(x+2)$

3 0

3 years ago

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