204,000 grapefruit.
There are 10 grapefruit in each box and there are 20,400 boxes; you need to multiply the number of grapefruits in each box (10) times the number of boxes (20,400)
10x20,400=204,000
Don't forget the units! In this problem, the units are grapefruit.
There an old algorythmic method similar to long division:-
7 . 4 8 3
-----------------
) 56. 00 00 00
7 ) 49
) ---
144 ) 7 00
) 576
----
148 8 ) 12400
) 11904
-------
) 496 00
1496 3 ) 44889
THis gives the square root as 7.48 to the nearest hundredth
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
1024
/ \
32 32
/ \ / \
8 4 8 4
/\ /\ /\ /\
(2) 4 (2) (2)(2) 4 (2) (2)
/\ /\
(2)(2) (2)(2)
2x2x2x2x2x2x2x2x2x2 or 2^10
*(There wasn’t a little 10 to use so I just put 2^10 which is two to the tenth power)
