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Olenka [21]
3 years ago
6

A candle is lit and burns and the length of the candle changes at a constant rate of -1.5 inches per hour. 2 hours after the can

dle was lit the candle is 8.2 inches long.
Write a formula that expresses the remaining length of the candle in inches, L, in terms of the number of hours t that have elapsed since the candle was lit.
Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

L = -1.5 \frac{in}{hr} t + 11.2

Step-by-step explanation:

For this case we need to define some notation:

L represent the remaining length of the candle in inches

t represent the time in hours that have elapsed since the candle was lit.

For this case we assume that L and f are related so then we can write this like that: L =f(t) L is a function of t.

And for this case we have a constant rate given of:

m = \frac{\Delta L}{\Delta t}= -1.5 \frac{in}{hr}

And we know a initial condition L(2) = 8.2 in

So then since we have a constant rate of change we can use a linear model given by:

L = m t +b

Where m is given and we need to find b. If we use the initial condition we have this:

8.2 = -1.5 \frac{in}{hr} (2) +b

And solving for b we got:

b = 8.2 +1.5*2=11.2 in

So then our lineal model would be given by:

L = -1.5 \frac{in}{hr} t + 11.2

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A. 2x-4y=\pi
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Step-by-step explanation:

A. 2x-4y=\pi. Any number could work as long as the coefficients for x and y stays the same. You are basically imposing that the quantity 2x-4y (if you bring 4y to the LHS) is equal to both -3 AND \pi, or any number you like. But yesterday was 3/14 so let's pick a fun number!

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ra1l [238]

Answer:   " x = 12 " .

________________________________________________

Step-by-step explanation:

________________________________________________

<u>Note</u>: If 2 (two) triangles are "similar" ;  then their corresponding sides are "proportional".

________________________________________________

Since one of the sides [the "hypotenuse"] of one the triangles given ; shows the measurement containing an expression with a value of "x" — specifically;  " 6x + 28 " ;  

    →  And since we want to solve for the value of "x" ;  we  use this "hypotenuse" of said particular triangle to set up a "proportion" with corresponding sides; so we can solve for "x" :

→  Set up proportions as a "ratio" ; or fraction:

       →  7:28::25:(6x + 28) ;  Solve for "x" ;

Let us write this in the form of a "fraction" :

      →  \frac{7}{28} = \frac{25}{(6x+28)} ;

________________________________________________

<u>Note</u>:  

        →  Rewrite:  " \frac{7}{28} " ; by simplifying to:

                                    " \frac{1}{4} " ;

________________________________________________

         →  Since:  " \frac{7}{28} " ;

              =  " (7÷7) / (28÷7) " ;

              =  " (1 /4) " ;

              =   " \frac{1}{4} " .

________________________________________________

Now, rewrite the "proportion" ; as follows:

________________________________________________

        \frac{1}{4} = \frac{25}{(6x+28)}  ;

________________________________________________

Now:   "Cross multiply" ;  that is:

______________________________________

→   Given:   " \frac{a}{b} = \frac{c}{d} " ;  

         and:  " b\neq0 " ;  " d\neq0 " ;

→  Then:   " a * d "  =  " b * c " .

________________________________________________

Likewise:   " 1(6x + 28)  =  (4) * (25) "   ;

______________________________________________

SImplify:    " 6x + 28 =  100 " ;  Solve for "x" ;

→ Subtract "28" from each side of the equation:

                  →   " 6x + 28 - 28 = 100 - 28 "  ;

    to get:   →   " 6x  =  72  "  ;

Now, divide each side of the equation by:  " 6 " ;

        to isolate "x" on one side of the equation; & to solve for "x" ; as follows:

   →   "  6x  =  72  "  ;

         →   6x / 6  =  72 / 6 ;

  to get:

         →   " x  = 12 "  ;

        →   which is the answer.

______________________________________________

Hope this helps!

  Best wishes in your academic pursuits

          — and within the "Brainly" community!

______________________________________________

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