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Sever21 [200]
3 years ago
6

Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed StartFraction 4 over 17 End

Fraction cups from the first orange, StartFraction 3 over 10 EndFraction cups from the second orange, StartFraction 9 over 20 EndFraction cups from the third orange, StartFraction 3 over 11 EndFraction cups from the fourth orange, and StartFraction 7 over 15 EndFraction cups from the fifth orange. Patel estimates that he needs 2 cups of orange juice for his family. About how much more orange juice does he need to reach his estimate?
Mathematics
2 answers:
IgorC [24]3 years ago
8 0

Answer:

\approx \frac{11}{40}

Step-by-step explanation:

Juice squeezed from first orange = \frac{4}{17} = 0.235

Juice squeezed from second orange = \frac{3}{10} = 0.3

Juice squeezed from third orange = \frac{9}{20} = 0.45

Juice squeezed from fourth orange = \frac{3}{11} = 0.27

Juice squeezed from fifth orange = \frac{7}{15} = 0.47

Total juice squeezed from all the five oranges = 0.235 + 0.3 + 0.45 + 0.27 + 0.47 = 1.725

Total juice to be squeezed = 2 cups

More juice required = 2 - 1.725 = 0.275 \approx \frac{11}{40}

Therefore, to make it 2 cups of orange juice for the family, about \approx \frac{11}{40} cups of more juice is required.

jasenka [17]3 years ago
5 0

Answer:

1 5/6

Step-by-step explanation: this is what i got from doing the math. please correct me if I'm wrong

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Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
Find sin theta if theta is an angle in standard position and the point with coordinates (3, -4) lies on the terminal side of an
alisha [4.7K]

Answer:

\sin \theta=-\frac{4}{5}

Step-by-step explanation:

Given:

Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).

So, the 'x' value is 3 and 'y' value id -4.

Using Pythagoras Theorem, we find the hypotenuse.

Hypotenuse = \sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

Now, using the sine ratio for the angle, we have

\sin \theta=\frac{Opposite}{Hypotenuse}\\\sin \theta=\frac{-4}{5}\\\sin \theta=-\frac{4}{5}

Therefore, the value of \sin \theta is -\frac{4}{5}.

The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,

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3 years ago
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X = -8.
subtract 19.
-X = 8
divide by -1.
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