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3 years ago

Jay was placed 32 seats in 4 rows for a debate what is the unit rate of seats per row ?

Mathematics

1 answer:

irinina [24]3 years ago

5 0

8
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32 in counting 8 per row

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Silva set up a dog-walking buisness. He earned $60 in June. He is projected to earn 110% more in July. How much is Silvia projec

Jlenok [28]

I think that gain of Silva, in July, is: 60+110100∗60=60+1110∗60=60+66=126$
so A.

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4 years ago

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Look at the pictures pleaseeeeee

Alex

Answer:

Step-by-step explanation:

There is missing information in the task: HD║FG !!!!!

∠HDE ≅ ∠FGE and ∠EHD ≅ ∠EFG

ΔEHG ~ ΔEFG (AAA theorem of similarity)

m∠F = 22°

m∠G = 89°

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3 years ago

Prove by mathematical induction that

postnew [5]

For $n=1$ , on the left we have $\cos\theta$ , and on the right,

$\dfrac{\sin2\theta}{2\sin\theta}=\dfrac{2\sin\theta\cos\theta}{2\sin\theta}=\cos\theta$

(where we use the double angle identity: $\sin2\theta=2\sin\theta\cos\theta$ )

Suppose the relation holds for $n=k$ :

$\displaystyle\sum_{n=1}^k\cos(2n-1)\theta=\dfrac{\sin2k\theta}{2\sin\theta}$

Then for $n=k+1$ , the left side is

$\displaystyle\sum_{n=1}^{k+1}\cos(2n-1)\theta=\sum_{n=1}^k\cos(2n-1)\theta+\cos(2k+1)\theta=\dfrac{\sin2k\theta}{2\sin\theta}+\cos(2k+1)\theta$

So we want to show that

$\dfrac{\sin2k\theta}{2\sin\theta}+\cos(2k+1)\theta=\dfrac{\sin(2k+2)\theta}{2\sin\theta}$

On the left side, we can combine the fractions:

$\dfrac{\sin2k\theta+2\sin\theta\cos(2k+1)\theta}{2\sin\theta}$

Recall that

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

so that we can write

$\dfrac{\sin2k\theta+2\sin\theta(\cos2k\theta\cos\theta-\sin2k\theta\sin\theta)}{2\sin\theta}$

$=\dfrac{\sin2k\theta+\sin2\theta\cos2k\theta-2\sin2k\theta\sin^2\theta}{2\sin\theta}$

$=\dfrac{\sin2k\theta(1-2\sin^2\theta)+\sin2\theta\cos2k\theta}{2\sin\theta}$

$=\dfrac{\sin2k\theta\cos2\theta+\sin2\theta\cos2k\theta}{2\sin\theta}$

(another double angle identity: $\cos2\theta=\cos^2\theta-\sin^2\theta=1-2\sin^2\theta$ )

Then recall that

$\sin(x+y)=\sin x\cos y+\sin y\cos x$

which lets us consolidate the numerator to get what we wanted:

$=\dfrac{\sin(2k+2)\theta}{2\sin\theta}$

and the identity is established.

8 0

3 years ago

What are the values of the function Y=3x-4 for x=0,1,2, and 3? (A) -4, -1, 2, 5 (B) 0, 3, 6, 9 (C) -4, 2, 5, 8 (D) 0, 1, 5, 9

mina [271]

(c)-4,2,5,8 is the answer

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3 years ago

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Please helppp ill give brainliestttttt

katrin [286]

Answer:

I dont understand? What is the question you are asking? Did you mean to add a photo?

Step-by-step explanation:

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3 years ago