Answer:
ab² - a²b
Step-by-step explanation:
a²b⁴ - b²a⁴ can be factored as a²b²(b² - a²) which becomes a²b²(b + a)(b - a). Since the numerator and denominator both have (a + b) and ab the final answer is ab(b - a) = ab² - a²b.
Answer:
The predicted number of catfish in the pond is 57.
Step-by-step explanation:
We are given that the average number of catfish in the samples was 5.7. If the total population of fish in the pond is 200, the proportion of catfish in the pond will be 5.7/20 = x/200.
We have to calculate the predicted number of catfish in the pond.
The given proportion to us is;
![\frac{5.7}{20}=\frac{x}{200}](https://tex.z-dn.net/?f=%5Cfrac%7B5.7%7D%7B20%7D%3D%5Cfrac%7Bx%7D%7B200%7D)
Cross multiplying both the fractions we get;
![5.7 \times 200=x \times 20](https://tex.z-dn.net/?f=5.7%20%5Ctimes%20200%3Dx%20%5Ctimes%2020)
![\frac{57}{10} \times 200=x \times 20](https://tex.z-dn.net/?f=%5Cfrac%7B57%7D%7B10%7D%20%20%5Ctimes%20200%3Dx%20%5Ctimes%2020)
![{57} \times 20=x \times 20](https://tex.z-dn.net/?f=%7B57%7D%20%5Ctimes%2020%3Dx%20%5Ctimes%2020)
![x = \frac{57 \times 20}{20}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B57%20%5Ctimes%2020%7D%7B20%7D)
So, the predicted number of catfish in the pond is 57.
Answer:
yes they are
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
mass of 100 centimeters of copper wire is ![2.00](https://tex.z-dn.net/?f=2.00)
so, mass of 1 centimeter of copper wire will be ![\frac{2}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B100%7D)
hence, 14 centimeters of copper wire will provide .28 copper