Yes for the first one, yes for the second one, and yes for the third one although your subtraction equation had the wrong year (its not 1847 its 1846) but the answer was right, 65.
Answer:
See explanation.
Step-by-step explanation:
We are looking at a geometric distribution.
The probability of selecting a brown peanut is .12 = p
The probability of not selecting a brown peanut is .88 = q
The probability mass function is p(y) = (.88)^(y-1) * (.12)
a) p(7) = (.88)^6 * .12 = .0557
b) p(7 <= y <= 8) = p(7) + p(8)
= .0557 + (.88)^7 * .12 = .1048
c) p(y <= 7) = p(0) + p(1) + ... + p(7)
= .12 + (.88)^1 * .12 + (.88)^2 * .12 + ... + (.88)^6 * .12 = .4713
d) The expect value is 1/p. So, 1/(.12) = 8.33 M&M's
Answer:
below
Step-by-step explanation:
Two students are selling cookies at a bake fair. Jake is selling cookies for $2.50 each plus $6 for the packaging. Kevin is selling cookies for $3.25 each plus $3 for the packaging. How ma cookies would both have to sell to make the same amount of money?
2.5x + 6 = 3.25x + 3
2.5x = 3.25x - 3
-0.75x = -3
x = 4 cookies
Best of Luck!
