Y = x^2 + 10x - 171
y = (x - 9)(x + 19)

x - 9= 0 x + 19 = 0
x = 9 x = -19

Answer B covers all requirements... the factored form is
y= (x + 19)(x - 9)
and the zeros are -19 and 9

3 0

3 years ago

A rectangles length is 2 meters greater than its width if the e perimeter is greater than 112 what is the rectangles possible wi

pishuonlain [190]

Answer:

Step-by-step explanation:

Perimeter of a rectangle = 2(L +W)

Given L = W + 2 and the perimeter is greater than 112 meters?

P rect < 2(L +W) L = W + 2

P rect < 2(W + 2 +W)

< 2(2W+2)

112 < 4W + 4 solve for W

(112 - 4)/4 < (4W +4 - 4)/4

108/4 < (4W + 0)/4

27 < W

the width has to be greater than 27 meters

5 0

3 years ago

Help me please solve the following equation for x.

wlad13 [49]

Answer:

x = 13

x = -5

Step-by-step explanation:

$\frac{(x-4)^2}{3}-13=14\\\frac{(x-4)^2}{3}=27\\(x-4)^2=81\\x-4=\sqrt{81}\\\\ x-4=9\\x=13\\\\x-4=-9\\x=-5$

5 0

2 years ago