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IRISSAK [1]
3 years ago
5

there are 27 small cubes arranged in a 3 by 3 by 3 cube. The top and sides of the cube are painted red. How many of the 27 small

cubes have 0 faces painted? 1 face? 2 faces? 3 faces? 4 faces? 5 faces? 6 faces?
Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

1 Face has 0 face painted

Step-by-step explanation:

As per the question a  painted cube that is cut into 27 equal-size smaller cubes has been cut into a 3 * 3 * 3 arrangement.

 

There is 1 cube in the very center

 On each of the 6 sides of the cube, there is a central smaller cube that is painted once.

 

Of the 27 (3*3*3) smaller cubes formed by the cutting, 1 gets no paint, 6 are painted on 1 face, 12 are painted on 2 faces, and 8 are painted on 3 faces (total 27 cubes).

1 (no paint) + 6 (painted 1) + 12 (painted 2) + 8 (painted 3) = 27 total

The sum of the painted faces (of the small cubes) is 54 (which is 6*9).

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726 times 5 is...
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The boys wrestling team scored a total of 36 points. Pins are worth 6 points. Major
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Answer:

6p + 4d = 36

Step-by-step explanation:

If p = number of pins and d = number of major decisions, then the equation is 6p + 4d = 36.

Hope this helps!

5 0
3 years ago
Find the area of the circle to the nearest whole number, if necessary!
astra-53 [7]

Answer:

The circle has an area of about 1385 square mm.

Step-by-step explanation:

Let's recall that circles have an area that can be found with the following formula:

A=\pi r^{2}

where r is the radius of the circle.

Now, focus your eyes on the circle. We are shown that the diameter of this circle is 42 mm, but we only want the radius. Since the radius is half the diameter, the radius is 21 mm. Now, we can solve for the area of the circle.

A=\pi (21)^2\\A=441\pi \\A=1385.44236...

So, to the nearest whole number, the area of the circle is 1385 square mm.

5 0
2 years ago
(b) find expressions for the quantities p2, p3, p4, . . ., and pn representing the amount of atenolol in the body right before t
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4 0
4 years ago
Please help me with this.
OLga [1]

Swapping rows alters the sign of the determinant:

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}

Multiplying a single row by a scalar scales the determinant by the same amount:

\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}

Then

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}

8 0
2 years ago
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