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IRISSAK [1]
3 years ago
5

there are 27 small cubes arranged in a 3 by 3 by 3 cube. The top and sides of the cube are painted red. How many of the 27 small

cubes have 0 faces painted? 1 face? 2 faces? 3 faces? 4 faces? 5 faces? 6 faces?
Mathematics
1 answer:
mars1129 [50]3 years ago
3 0

1 Face has 0 face painted

Step-by-step explanation:

As per the question a  painted cube that is cut into 27 equal-size smaller cubes has been cut into a 3 * 3 * 3 arrangement.

 

There is 1 cube in the very center

 On each of the 6 sides of the cube, there is a central smaller cube that is painted once.

 

Of the 27 (3*3*3) smaller cubes formed by the cutting, 1 gets no paint, 6 are painted on 1 face, 12 are painted on 2 faces, and 8 are painted on 3 faces (total 27 cubes).

1 (no paint) + 6 (painted 1) + 12 (painted 2) + 8 (painted 3) = 27 total

The sum of the painted faces (of the small cubes) is 54 (which is 6*9).

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sergiy2304 [10]

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Answer:

see explanation

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VX = \frac{7}{cos41} ≈ 9.3

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tan41° = \frac{opposite}{adjacent} = \frac{WX}{VW} = \frac{WX}{7}

Multiply both sides by 7

7 × tan41° = WX, thus

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The sum of the 3 angles in a triangle = 180°

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