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3 years ago

If 2 kilograms of strawberries cost $4.50, how much would 3 kilograms cost?

Mathematics

1 answer:

guajiro [1.7K]3 years ago

8 0

Find the cost of 1 kilogram, by dividing the cost of 2 by 2:

4.50 / 2 = $2.25 per kilogram.

Now multiply the cost of 1 by 3:

2.25 x 3 = $6.75 for 3 kilograms.

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If f(x)=2x+5 and g(x)=x²+5, evaluate the functions:

Ostrovityanka [42]

Answer:

f(-3) = -1

g(-3) = 14

Step-by-step explanation:

plug -3 for x to get the answer

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3 years ago

Read 2 more answers

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Masja [62]

Answer: $\frac{x-4}{2x-2}$

Step-by-step explanation:

$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .

The equation we get is:

$\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}$

With this equation, we can factor each equation:

$\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}$

We can cancel out like terms since they would be dividing each other:

$\frac{x-4}{2x-2}$

8 0

3 years ago

Write -4i+(1/4-5i)-(-3/4+8i)+17i as a complex number in the standard for

KatRina [158]

Answer:

$1+ 0i$

Step-by-step explanation:

A complex number is a number which has some real part and some imaginary part.

Standard form of a complex number is represented as

$a +bi$

Where $a$ is the real part,

and $bi$ is the imaginary part.

And $i = \sqrt{-1}$

Given complex number:

$-4i+\dfrac{1}{4}-5i)-(-\dfrac{3}{4}+8i)+17i\\\Rightarrow -4i+\dfrac{1}{4}-5i + \dfrac{3}{4}-8i+17i\\\Rightarrow \dfrac{3}{4}+\dfrac{1}{4}-4i -5i-8i+17i\\\Rightarrow \dfrac{3+1}{4}-17i+17i\\\Rightarrow \dfrac{4}{4}+0i\\\Rightarrow 1 + 0i$

Hence, the standard form is $1+ 0i$ .

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2 years ago

Several students from boxerville middle stood in a circle, evenly spaced, to play a game. If the 6th student was directly across

myrzilka [38]

Answer:

There were 14 students in the circle

Step-by-step explanation:

* Lets explain how to solve the problem

- The students stood in a circle

∴ The line joining each two opposite students is the diameter

of the circle

- The 6th student was directly across from the 13th student

∴ The 6th student is opposite to the 13th student

- Lets count how many students between 6th student and

13th student

∵ 7th , 8th , 9th , 10th , 11th , 12th students between the 6th

student and 13th student

∴ There are 6 students between them

- Lets count how many students between 13th student and

6th student

∵ 14th , 1st , 2nd , 3rd , 4th , 5th students between the 13th

student and 6th student

∴ There are 6 students between them

∵ There are 6 students between 6th and 13th

∵ There are 6 students between 13th and 6th

∵ There are 2 students in 6th and 13th

∴ The number of the students = 6 + 6 + 2 = 14

∴ There were 14 students in the circle

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3 years ago

Please help and solve for x! (: thank you in advance.

Vera_Pavlovna [14]

First look at the given numbers, especially 123 degrees which if you add up the other side it equals 180 degrees so:
180-123= 57
Ok now you know two sides of the triangle and you know that all the 3 sides add up to 360 degrees so:
57+75= 132
180-132= 48

6 0

3 years ago