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3 years ago

10

If 2 kilograms of strawberries cost $4.50, how much would 3 kilograms cost?

1 answer:

guajiro [1.7K]3 years ago

8 0

Find the cost of 1 kilogram, by dividing the cost of 2 by 2:

4.50 / 2 = $2.25 per kilogram.

Now multiply the cost of 1 by 3:

2.25 x 3 = $6.75 for 3 kilograms.

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What is the area of a sector when r = 2 and 0 = 1.75 radians? [?] sq units Round your answer to the nearest tenth. Enter

krok68 [10]

Answer:

Step-by-step explanation:

The area of a sector in terms of radians as opposed to degrees is

$A=\frac{\theta}{2\pi }*\pi r^2$

Filling in the formula accordingly gives us

$A=\frac{1.75rad}{2\pi rad}*\pi (2)^2$

The radians cancel out, the pi's cancel out, the 2 in the denominator cancels out (divides into 2-squared once), leaving us with

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1 year ago

What is the solution to the linear equation 4b + 6 = 2 - b+ 4

inessss [21]

Final Answer: $b = 0$

Steps/Reasons/Explanation:

Question: What is the solution to the linear equation $4b + 6 = 2 - b + 4$ ?

<u>Step 1</u>: Simplify $2 - b + 4$ to $6 - b$ .

$4b + 6 = 6 - b$

<u>Step 2</u>: Cancel $6$ on both sides.

$4b = -b$

<u>Step 3</u>: Subtract $-b$ from both sides.

$4b + b = 0$

<u>Step 4</u>: Simplify $4b + b$ to $5b$ .

$5b = 0$

<u>Step 5</u>: Divide both sides by $5$ .

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~I hope I helped you :)~

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3 years ago

What value of k makes the equation true? (5a^2 b^3)(6a^k b)=30a^6 b^4

Ratling [72]

we are given

$(5a^2 b^3)(6a^k b)=30a^6 b^4$

Firstly, we will simplify left side

and then we can solve for k

Left side is

$(5a^2 b^3)(6a^k b)$

we can arrange like terms

$(5a^2 6a^k)(b^3 b)$

$(5\times 6 a^2a^k)(b^3 b)$

$(30 a^2a^k)(b^3 b^1)$

now, we can use property of exponent

$a^m \times a^n=a^{m+n}$

$(30 a^{2+k})(b^{3+1})$

$30a^{2+k}b^{4}$

now, we can equate it with right side

and we get

$30a^{2+k}b^{4}=30a^6 b^4$

We can see that both sides have 30 , a and b

and they are equal

so, exponent of a must also be equal

$2+k=6$

now, we can solve for k

$2+k-2=6-2$

$k=4$ ................Answer

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ahrayia [7]

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