Answer:
The left one...
Step-by-step explanation:
I just jocking. You can't ask questions like this without a photo or at lease explain what is on the photo.
Answer:
Step-by-step explanation:
The function that could model this periodic phenomenon will be of the form
The tide varies between 3ft and 9ft, which means its amplitude 
is
and its midline 
is
.
Furthermore, since at 
the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is 
.
The period of the full cycle is 14 hours, which means
giving us
With all of the values of the variables in place, the function modeling the situation now becomes
The answer is b i show the working out in this photo
Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )
Step-by-step explanation:
Given the data in the question;
n1 = 72, n2 = 17
P1 = 54 / 72 = 0.75
P2 = 10 / 17 = 0.5882
so
P_good = 0.75
P_bad = 0.5882
standard ERRROR will be;
SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]
SE = √( 0.002604 + 0.01424)
SE = 0.12978
given confidence interval = 90%
significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645 { from standard normal table}
so
93% CI is;
(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad< (0.75 - 0.5882) + 1.645×0.12978
⇒0.1618 - 0.2134 <P_good - P_bad< 0.1618 + 0.2134
⇒ - 0.0516 <P_good - P_bad< 0.3752
Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )
I’m just trying so much better to talk now but it’s just a good 256
