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zavuch27 [327]
3 years ago
11

I could use some help!! (worth 25 points)​

Mathematics
2 answers:
lawyer [7]3 years ago
8 0

Answer:

Step-by-step explanation:

100m

Verizon [17]3 years ago
6 0

Answer:

i think its 116.6m but im not sure

plz mark me as brainliest if i was right :)

You might be interested in
Write an equation of the lines passes through (4,1) and is parallel to y= -2x+7
Nastasia [14]

Answer:

y = -2x + 9

Step-by-step explanation:

The parallel line has an equation of y = -2x + 7;

And its slope is -2.

The slope of the line that passes through (4,1) is also -2 since parallel lines have the same slope.

Taking another point (x,y) on the line that passes through (4,1):

slope(m) = change in y ÷ change in x

-2 = \frac{y - 1}{x - 4}

Cross multiplying gives;

y - 1 = -2x + 8

y = -2x + 9

5 0
3 years ago
Determine whether the parabola y = −x2 + 15x + 8 opens up, down, left, or right.
spayn [35]
Dy/dx=-2x+15

d2y/dx2=-2

Since the acceleration is a constant negative it has an absolute maximum value for y(x), thus it opens downward, as x decreases without bound as x approaches ±∞
7 0
3 years ago
PLZ HELP WILL MARK BRAINLIEST
Fantom [35]

Answer:

  g(x) = (1/6)(x +7)^2 -8

Step-by-step explanation:

The transformation ...

  g(x) = a·f(x -h) +k

represents vertical scaling by a factor of 'a', right shift by h units, and up shift by k units. You want the function g(x) for f(x) = x^2, a = 1/6, h = -7, and k = -8. Those transformations give you ...

  g(x) = (1/6)(x +7)^2 -8

6 0
4 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
The price h of a recently bought house plus 10% property tax
Bogdan [553]
H + 0.10h would be ur expression
8 0
4 years ago
Read 2 more answers
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