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andrey2020 [161]
3 years ago
12

A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. Each

small box of paper weighs 35 pounds and each large box of paper weighs 65 pounds. A total of 22 boxes of paper were shipped weighing 1040 pounds altogether. Determine the number of small boxes shipped and the number of large boxes shipped.
Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:

35-=13 boxes ; 65-9 boxes

Step-by-step explanation:

35 x X+ 65 (22-x)=1040

35x+1430-65x=1040

1430-30x=1040

30x=390

x =390/30=13

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5 - 3tan3x = 0 trên -π< x < π.
serious [3.7K]

Answer:

x = 0.343

Step-by-step explanation:

We want to solve:

5 - 3tan(3x) = 0

such that:

-π< x < π

where π = 3.14

then:

-3.14 < x < 3.14

Let's solve the equation:

5 - 3tan(3x) = 0

-3tan(3x) = -5

tan(3x) = -5/-3 = 5/3

Now we can use the inverse tan function, Atan(x).

Remember that:

Atan( tan(x) ) = tan( Atan(x)) = x

Then if we apply that function to both sides, we get:

Atan( tan(3x)) = Atan(5/3)

3x = Atan(5/3)

x = Atan(5/3)/3 = 0.343

4 0
3 years ago
16 + 32 ÷ 4 + (10 - 6)2
fenix001 [56]

Answer:

16+32÷4+(10-6)2=16+8+8=32

8 0
3 years ago
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PLEASE HELP IMPORTANT MATH
VladimirAG [237]

A and C are the correct answers

5 0
4 years ago
The probability that a lab specimen contains high levels of contamination is 0.12. A group of 4 independent samples are checked.
sergiy2304 [10]

Answer:

0.5996 is the probability that none contain high levels of contamination.

Step-by-step explanation:

We are given the following information:

We treat  lab specimen containing high levels of contamination as a success.

P( lab specimen containing high levels of contamination) = 0.12

Then the number of lab specimens follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 4

We have to find the probability that none of the lab specimen consist of high level of contamination.

We have to evaluate:

P(x = 0)\\= \binom{4}{0}(0.12)^0(1-0.12)^{(4-0)}\\= 0.5996

0.5996 is the probability that none contain high levels of contamination.

5 0
4 years ago
1. Rewrite the equation 5(x - 3) = x + 13 with 6 substituted for x. Write a
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

5(6-3)=6+13 -simplify

30-15=6+13

15=19

x doesnt equal 6

5(x-3)=x+13

5x-15=x+13

4x=28

x=7

4x=28

4(7)=28

28=28

4 0
3 years ago
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