if they had spend 1500 total for goods and expenses 500 which is total 2000 and
revenue is 3000
1500 + 500 - 3000 = 1000 is profit for the business
Given:
The system of equations:


To find:
The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.
Solution:
We have,
...(i)
...(ii)
The coefficient of x in (i) and (ii) are 1 and
respectively.
To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.
It means, we have to convert
into -1. It is possible if we multiply the equation (ii) by -5.
On multiplying equation (ii) by -5, we get
...(iii)
On adding (i) and (iii), we get

Here, x is eliminated.
Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.
is the question multiple choice? if not I'd go with absolute value
Answer:
v= -2
Step-by-step explanation:
10+2v=−6(3v+5)
Step 1: Simplify both sides of the equation.
10+2v=−6(3v+5)10+2v=(−6)(3v)+(−6)(5)(Distribute)10+2v=−18v+−302v+10=−18v−30Step 2:
Add 18v to both sides.
2v+10+18v=−18v−30+18v20v+10=−30
Step 3:
Subtract 10 from both sides
.20v+10−10=−30−1020v=−40
Step 4:
Divide both sides by 20.20v20=−4020v=−2
Answer:v=−2
Answer:
Distribute 1.2 to 6.3 and -7x
Combine 3.5 and 7.56
suhtract 11.06 from both sides