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3 years ago

PLS HELP ME FOR 4, 5, and 6 ASAP GUYSSS ( SHOW WORK!!) + lots of POINTS!!

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

6 0

4. D
12/15 isn't the same as 30/40. 12/15=0.8, while 30/40=0.75. All the other options are equal.

5. C
Of course, you could figure this out by plugging in all the answers, and seeing which ones make the two sides equal, however, cross multiplying (multiplying the top of one fraction with the bottom of the other fraction) would be much faster. This will be your equation: 8*46=18*n. After combining like terms and dividing, you should find that n=20.

6. A
This problem is basically the same as #5. Cross multiplying so the equation you get will be 0.6*1.2=1.6*w. W should be 0.45.

Hope this helps!!

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Solve the following equation and identify the missing variable 7x + 3=2x + 13

const2013 [10]

Answer:

Step-by-step explanation:

7x+3=2x+13

7x-2x=13-3

5x=10

$\frac{5x}{5}$ = $\frac{10}{5}$

x=2

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4 years ago

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One number is 6 more than another. the difference between their squares is 192. what is the numbers?

Masteriza [31]

Let the number be x.
then the number is (x + 6)
the difference between their squares is 192
(x + 6)² - x² = 192

expanding we get;

x² + 12x + 36 - x² = 192
12x + 36 = 192
12x = 192 - 36
12x = 156
x = 13

the numbers are 13 and 19.

hope this helps, God bless!

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3 years ago

At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

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3 years ago

Expand the following:<br> a) x(x - 6)<br> b) x(4x + 1)<br> c) 2x(5x + 4)<br> d) 3x(5x - y)

puteri [66]

Answer:

Step-by-step explanation:

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