Answer:
Step-by-step explanation:
![if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) = {4}^{2} \\ f[g(4)] = 4( {4}^{2} ) + 2 \\ f[g(4)] = 4(16) + 2 \\ f[g(4)] =64 + 2 \\ f[g(4)] = \boxed{66}](https://tex.z-dn.net/?f=%20if%20%5C%3A%20the%20%5C%3A%20question%20%5C%3A%20is%20%5C%3A%20f%5Bg%284%29%5D%20%5C%5C%20then%20%5C%3A%20at%20%5C%3A%20first%20%5C%3A%20solve%20%5C%3A%20for%20%5C%3A%20g%284%29%20%5C%5C%20g%284%29%20%3D%20%20%7B4%7D%5E%7B2%7D%20%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%28%20%7B4%7D%5E%7B2%7D%20%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%2816%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D64%20%2B%202%20%5C%5C%20%20%20f%5Bg%284%29%5D%20%20%3D%20%20%5Cboxed%7B66%7D)
In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
<h3>What is the proof about?</h3>
Note that:
AB = 12
AC = 6.
BC = AB - AC
= 12 - 6
=6
So, AC, BC= 6
Since C is in the middle, one can say that C is the midpoint of AB.
Note that the use of segment addition property shows: AC + CB = AB = 12
Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6
Therefore, AC = CB and thus In proving that C is the midpoint of AB, we see truly that C has Symmetric property.
See full question below
Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive
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Answer: (-1, 2)
explanation:
3(2x-y=-4)
6x-3y=-12
9x+3y=-3
6x-3y=-12
15x=-15
x=-1
2(-1) - y = -4
-2-y=-4
-y=-2
y=2
