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leva [86]
3 years ago
10

Solve the problem as directed. The time it takes to lay a sidewalk of a certain type varies directly as the length and inversely

as the number of men working. If eight men take two days to lay 100 feet, how long will three men take to lay 150 feet?
Mathematics
2 answers:
Sever21 [200]3 years ago
5 0
T = k L / N   where k is the constant of variation

2 = k * 100 / 8 
100k =  16
k = 0.16  

so fromula is

T = 0.16L / N

when L = 150 and N = 3 we have

Time taken T = 016* 150 / 3 =  8 days answer
atroni [7]3 years ago
3 0
150/18.75=18.75 feet per day
150/18.75=17.14 days
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Is floor(x) periodic?
diamong [38]

If you look at the graph of y = floor(x), you'll see a stairstep pattern that climbs up as you read from left to right. There are no vertical components to the graph. There are only horizontal components.

The graph is not periodic because the y values do not repeat themselves after a certain x value is passed. For instance, start at x = 0 and go to x = 3. You'll see the y values dont repeat themselves as if a sine function would. If you wanted the function to be periodic, the steps would have to go downhill at some point; however, this does not happen.

Conclusion: The function floor(x) is <u>not</u> periodic.

4 0
3 years ago
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Peters glasses each hold 8 fluid ounces how many glasses of juice can peter pour from a bottle that holds 2 quarts
kotykmax [81]
He can pour 8 glasses
5 0
2 years ago
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Find the<br>degree of the algebraic<br>expression:<br>3x^3 + 3x^2y^2 - y^2​
Ghella [55]

Answer:

Degree 4

Step-by-step explanation:

Expression:

3x^3 + 3x^2y^2 - y^2​

  • 3x^3 - degree 3
  • 3x^2y^2 - degree 2+2 = 4
  • y^2​ - degree 2

So the expression has degree 4 as per the highest degree of the terms

4 0
3 years ago
Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
Which ordered pair is a solution to the system of equations?
emmainna [20.7K]

Answer: B(7, – 5)

Step-by-step explanation:

4 0
3 years ago
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