Find thedegree of the algebraicexpression:3x^3 + 3x^2y^2 - y^2

Mathematics

1 answer:

Ghella [55]2 years ago

4 0

Answer:

Degree 4

Step-by-step explanation:

Expression:

3x^3 + 3x^2y^2 - y^2

3x^3 - degree 3
3x^2y^2 - degree 2+2 = 4
y^2 - degree 2

So the expression has degree 4 as per the highest degree of the terms

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Best explained and correct answer gets brainliest.

topjm [15]

U = (-2,3)

V = (3,0)

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= ( (3-2)/2 , (3+0)/2 )

= ( 1/2 , 3/2)

= ( 0.5 , 1.5)

X = (0.5 , 1.5) [from fig]

midpoint of UV = X

W= (-2,-3)

V =( 3.0)

Y = ( (-2+3)/2 , (-3+0)/2 )

= (0.5 , - 1.5)

Y = ( 0.5 , -1.5) [ from fig ]

Y is the midpoint of WV

by midpoint theorem ,

UW = 2( XY )

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2 years ago

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Tpy6a [65]

The answer is 2 first you add then multiple

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2 years ago

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