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Delicious77 [7]
3 years ago
14

Find thedegree of the algebraicexpression:3x^3 + 3x^2y^2 - y^2​

Mathematics
1 answer:
Ghella [55]3 years ago
4 0

Answer:

Degree 4

Step-by-step explanation:

Expression:

3x^3 + 3x^2y^2 - y^2​

  • 3x^3 - degree 3
  • 3x^2y^2 - degree 2+2 = 4
  • y^2​ - degree 2

So the expression has degree 4 as per the highest degree of the terms

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The number of males in the classroom is three more than twice the number of females. Of the total number of students is 57, how
dolphi86 [110]

Answer:

Step-by-step explanation:

Given that the number of males in the classroom is three more than twice the number of females.

the total number of students is 57

Let x be the no of males then no of females = 57-x

Also we have 3 more than twice no of females as

2(57-x)+3

This equals x

2(57-x)+3=x\\114-2x+3=x\\3x=117\\x=39

No of males = 39, no of females = 18

6 0
3 years ago
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Answer:

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5 0
1 year ago
Which of the following represents 3x-5y+10=0 written in slope-intercept form?
taurus [48]

For this case we have that by definition, the equation of a line in the slope-intercept form is given by:

y = mx + b

Where:

m: Is the slope

b: Is the cut-off point with the y axis

We have the following equation:

3x-5y + 10 = 0

We manipulate algebraically:

We subtract 10 from both sides of the equation:

3x-5y = -10

We subtract 3x from both sides of the equation:

-5y = -3x-10

We multiply by -1 on both sides of the equation:

5y = 3x + 10

We divide between 5 on both sides of the equation:

y = \frac {3} {5} x + \frac {10} {5}\\y = \frac {3} {5} x + 2

Thus, the equation in the slope-intercept form is y = \frac {3} {5} x + 2

Answer:

y = \frac {3} {5} x + 2

5 0
3 years ago
How do you decide which variable to isolate in order to use the substitution method to solve a system of linear equation?​
Kazeer [188]
It doesn’t really matter which variable you isolate first but usually you would use the one that’s by itself already. like for example one of the equations was y = 8. you would already have your y solve for so you would just have to plug that in for y in the other equation. personally, i usually do x first unless one of the equations has either x or y by itself already. i think its easier to just do x first and then solve for y after that, but it just depends on what the equations are; sometimes it might be easier to just do y first. hope this helps!
5 0
2 years ago
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