The amount of a sample remaining after t days is given by the equation P(t)=A(1/2)^(t/h), where A is the initial amount of the s
2 answers:
The equation is:
P ( t ) = A * (1/2 )^(t/h)
If a sample contains 18% of the original amount of Radon - 222 and h = 3.8:
0.18 * A = A * ( 0.5 )^(t/3.8) / : A ( we will divide both sides of the equation by A )
0.18 = ( 0.5 )^(t/3.8)
t / 3.8 = 2.47 ≈ 2.5
t = 3.8 * 2.5 = 9.5
Answer:
The best estimate for the age of the sample is 9.5 days.
P ( t ) = A * (1/2 )^(t/h)
If a sample contains 18% of the original amount of Radon - 222 and h = 3.8:
0.18 * A = A * ( 0.5 )^(t/3.8) / : A ( we will divide both sides of the equation by A )
0.18 = ( 0.5 )^(t/3.8)
t / 3.8 = 2.47 ≈ 2.5
t = 3.8 * 2.5 = 9.5
Answer:
The best estimate for the age of the sample is 9.5 days.
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<u>Complete question:</u>
Refer the attached diagram
<u>Answer:</u>
In reference to the attached figure, (-∞, 2) is the value where (f-g) (x) negative.
<u>Step-by-step explanation:</u>
From the attached figure, it shows that given data:
f (x) = x – 3
g (x) = - 0.5 x
To Find: At what interval the value of (f-g) (x) negative
So, first we need to calculate the (f-g) (x)
(f – g ) (x) = f (x) – g (x) = x-3 - (- 0.5 x)
⇒ (f - g) (x) =1.5 x - 3
Now we are supposed to find the interval for which (f-g) (x) is negative.
⇒ (f - g) (x) = x - 3+ 0.5 x = 1.5 x – 3 < 0
⇒ 1.5 x – 3 < 0
⇒ 1.5 x < 3
⇒
⇒ x < 2
Thus for (f - g) (x) negative x must be less than 2. Thereby, the interval is (-∞, 2). Function is negative when graph line lies below the x - axis.
