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3 years ago

Y varies directly with x, and y = 7 when x = 2. What is the value of y when x = 5?

1 answer:

3 0

Y varies directly with x" means y = constant * x or y = kx ----- (1)1. when x = -1/2, y = 2Put it in (1):2 = k * (-1/2)multiply by 2:4 = k * (-1)4 = -kk = -4y = -4x
"find the value of y when x= -0.3"y = -4x = (-4) * (-0.3) = 1.2

So for each problem, start with y = kxThey give you one x and one y value.Put it in y = kx and find k.Then put x = -0.3 and find y.

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Scott makes a scale drawing of a rectangular park. He uses the scale 5 centimeters: 3 meters. The length of his drawing is 20 ce

Svet_ta [14]

Answer:

The area of the park is $108\ m^{2}$

Step-by-step explanation:

we know that

The scale drawing is $\frac{5}{3}\frac{cm}{m}$

step 1

Find the actual length of the rectangular park

Divide the length in the drawing by the scale drawing

$20/(5/3)=12\ m$

step 2

Find the actual width of the rectangular park

Divide the width in the drawing by the scale drawing

$15/(5/3)=9\ m$

step 3

Find the area of the park

$A=(12)(9)=108\ m^{2}$

5 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

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horsena [70]

Ur giving 5 .........

4 0

3 years ago

The total weight of the golf balls from Julio’s golf bag was 273 grams. If each golf ball weighed 45.5 grams, which graph shows

MariettaO [177]

ANSWER:

EXPLAIN:

Since all the six balls have same weight and the total weight is given as 273g, then weight of one ball will be

273/6=45.5 g

1 ball=45.5 g

2 balls =2*45.5=91 g

3 balls =3*45.5=136.5 g

4 balls=4*45.5=182 g

5 balls =5*45.5=227.5 g

6 balls =6*45.5=273 g

7 0

2 years ago

Linear equations

yarga [219]

1. x = 2
2. x = 9
3. a = 3
4. x = 13
5. c = 3
6. s = 3
7. x = 7
8. c = 0
9. b = 1
10. c = 4
11. x = 4
12. x = 8
13. x = 12
14. y = 10
15. x = 11
16. x = 10
17. x = 6
18. x = 11

8 0

2 years ago