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daser333 [38]
4 years ago
10

How do i solve this problem ? (2xy)(3y)

Mathematics
1 answer:
Alla [95]4 years ago
6 0
6xy^2

The correct answer is 6xy squared
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URGENT: statistics: A researcher wishes to estimate the percentage of adults who support abolishing the penny what size sample s
irina1246 [14]

Using the margin of error for the z-distribution, the sample sizes are given as follows:

a) 822.

b) 1068.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

We have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Item a:

The estimate is of \pi = 0.26, hence we solve for n when M = 0.03.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.26(0.74)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.26(0.74)}

\sqrt{n} = \frac{1.96\sqrt{0.26(0.74)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.26(0.74)}}{0.03}\right)^2

n = 821.2

A sample of 822 is needed.

Item b:

No prior estimate, hence \pi = 0.5.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 1067.11

A sample of 1068 is needed.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
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