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3 years ago

8

Please someone help! i will give brainliest

1 answer:

frozen [14]3 years ago

5 0

Answer:

11

Step-by-step explanation:

proportions

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What is a slope of a line between the x-axis and y-axis

Georgia [21]

Answer:

Mercedes, look at the graph i'm attaching... do you see ? what's the slope?

Step-by-step explanation:

4 0

3 years ago

Suppose that y varies directly with x and y=10 when x=20. What is y when x=15

Likurg_2 [28]

Answer:

y=kx

subst y=10 and x=20 into the above

<em>1</em><em>0</em><em>=</em><em>k20</em>

<em>k</em><em>=</em><em>1</em><em>0</em><em>/</em><em>2</em><em>0</em>

<em>k</em><em>=</em><em>1</em><em>/</em><em>2</em>

<em>therefore</em><em> </em><em>relationship</em><em>:</em><em> </em><em>y</em><em>=</em><em>1</em><em>/</em><em>2</em><em>x</em>

<em>subst</em><em> </em><em>x</em><em>=</em><em>1</em><em>5</em><em> </em><em>into</em><em> </em><em>the</em><em> </em><em>relationship</em>

<em> </em><em>y</em><em>=</em><em>1</em><em>/</em><em>2</em><em>(</em><em>1</em><em>5</em><em>)</em>

<em>y</em><em>=</em><em>7</em><em>,</em><em>5</em>

Step by step explanation:

Step 1: when they say y varies directly with x they mean<em> y is proportional to x</em>
step 2: so y=kx where <em>k is the constant</em>
step 3: is to substitute <em>y=10</em> and <em>x=20</em> into the above equation y=kx
step 4: you will end up with <em>10=k20</em> then divide both sides by 20 so that <em>k becomes the subject of the formula </em>
step 5: your answer from the above will be <em>k=10/20 </em>so the relationship is <em>y is directly proportional to 1/2 x </em>what you did here is that you substituted k for 1/2 in the equation in step 3
step 6: is to finally substitute x=15 into the equation <em>y=1/2x</em> to finally get your answer <em>y</em><em>=</em><em>7</em><em>,</em><em>5</em><em>.</em>

4 0

3 years ago

Minerva starts a savings account with $50. The interest on the account balance is compounded annually. The graph below shows the

rodikova [14]

We can set up this equation using this formula:

a = p(1 + r/n)^nt

p = starting amount.

r = interest.

n = number of times it's compounded in a year

t = years

We'd set it up like this:

a = 50(1 + ?/1)^1(12)

Because we're missing the amount of interest, it would be impossible to tell what the amount would be after 12 years.

6 0

3 years ago

Please help me with #2!!!!

Natali [406]

D. 5

It is what it is

8 0

3 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

3 years ago