Answer:
Thermohaline circulation is influenced by changes in density gradients. These density gradients are affected by the salinity and temperature of the ocean’s water. Cold water is denser than warm water and salt water is denser than freshwater. As water cools off, it sinks. As water evaporates, the salt concentration of the remaining water increases because the salt from the evaporated water remains. This causes the water to sink and circulate.
Explanation:
Answer:
True
Explanation:
Since it's a passive way of transport, it is in favor of the concentration gradient and does not need to use ATP.
Mmmmmm mercury sexiest planet thanks for the pic
Answer:
The correct answer is option a. "7.1".
Explanation:
One easy way to determine if a peptide sequence is acidic, basic or neutral is to check for the number of amino acid residues that are acidic, basic or neutral. In this case, most amino acid residues are neutral, which mean that under neutral conditions they have a pKa close to 7.0. Particularly, the content of 3 leucine, 2 alanine and 2 glycine residues determines that the peptide have a pI of around 7.1.
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
