Answer:
0
Step-by-step explanation:
Let X to be a random variable that looks a binomial distribution which denoted the number of employees out of the 281 who earn the prevailing minimum wage or less
The sample size n = 281
The population parameter p = 5% = 0.05
Using normal approximation for the mean.
The standard deviation is:
By using continuity correction; the sample mean x is:
x = 30 - 0.5
x = 29.5
The z statistic test can now be as follows:
Z = 4.23
Thus, the probability that company A will get a discount is
P(X ≥ 30) = P(Z >4.23)
= 1 - P(Z < 4.23)
By using the Excel function for the z score 4.23 i.e. "=1 - NORMSDIST(4.23)" we get;
= 0.0000
The answer is 18.
If you multiple 3 x 3 x 2 you get 18 different ways to arrange the books
Re-arranging the numbers;
13.0, 13.5, 13.6, 14.1, 14.8, 15.8, 19.1, 21.6, 26.0, 30.8
Mean, x_bar = (13.0+13.5+13.6+14.1+14.8+15.8+19.1+21.6+26.0+30.8)/10 = 18.23
Standard deviation, sigma = Sqrt [{(13-18.23)^2+(13.5-18.23)^2+(13.6-18.23)^2+(14.1-18.23)^2+(14.8-18.23)^2+(15.8-18.23)^2+(19.1-18.23)^2+(21.6-18.23)^2+(26-18.23)^2+(30.8-18.23)^2}/10] = Sqrt [{27.3529+22.3729+21.4369+17.0569+11.7649+5.9049+0.7569+11.3569+60.3729+158.0049}/10] = Sqrt [336.381/10] = 5.8
Therefore,
x_bar = 18.23
sigma = 5.8
At 99% confidence, Z = 2.58
Confidence interval = x_bar +/- Z*sigma/Sqrt (n) = 18.23+/- 2.58*5.8/Sqrt (10) = 18.23+/-4.73 = [(18.23-4.73), (18.23+4.73)] = [13.5,22.96]
Answer: 0.56967905
Steps:
Raise 0.06 to the power of 1/5
0.56967905
