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3 years ago

The 2's in 42,256 what do that mean

Mathematics

1 answer:

Leno4ka [110]3 years ago

5 0

Answer:

4<u>2</u>256 is in the thousands place

42<u>2</u>56 is in the hundreds place

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Name the values of the given digits the 4s in a 4400

IRISSAK [1]

The values of 4s that are present in 4400 are 4 thousands and 4 hundreds.
4400 = 4 thousands + 4 hundreds + 0 tens + 0 ones
so the value of first 4 is 4 thousands and second 4 is 4 hundreds.

5 0

4 years ago

A square measures 17r on each side. Which monomial represents the area of the square?

Eduardwww [97]

Answer:

Area of square = 289r²

Step-by-step explanation:

Given:

Side of square = 17r

Find:

Area of square

Computation:

Area of square = side²

Area of square = (17r)²

Area of square = 289r²

5 0

3 years ago

The weight of a box varies directly as the volume of the box . If a 138 - pound box has a volume of 23 gallons , what is the wei

Marizza181 [45]

Answer:

150 lb

Step-by-step explanation:

138lb/23 gal = x/25 gal

cross multiply and solve for x

23x = 138·25

x = 3450/23

x = 150 lb

3 0

3 years ago

Which factors the 32 at 48 comment

finlep [7]

48-32=16
so yur answer is 16
hope it helped

4 0

4 years ago

Read 2 more answers

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time ca

aleksandr82 [10.1K]

Answer:

(a)8.0mg

(b)36.87 hours

(c)-0.168

Step-by-step explanation:

The amount of Valium in that person's bloodstream at any time can be modeled with the exponential decay function $A ( t ) = 10 e^{ -0.0188 t$ (t in hours)

(a)After 12 Hours

$A ( 12) = 10 e^{ -0.0188*12}\\=7.98\\\approx 8.0 mg $(to the nearest tenth of a milligram)$

(b)If A(t)=5mg

Then:

$5= 10 e^{ -0.0188 t}\\$Divide both sides by 10\\0.5=e^{ -0.0188 t}\\$Take the natural logarithm of both sides\\ln (0.5)=-0.0188 t\\t=ln (0.5) \div (-0.0188)\\$t=36.87 hours (to two decimal places.)$

(c)

$A ( t ) = 10 e^{ -0.0188 t}\\A'(t)=10(-0.0188)e^{ -0.0188 t}\\A'(t)=-0.188e^{ -0.0188 t}\\$At 6 hours, the rate at which the amount of Valium is decaying therefore is:\\A'(6)=-0.188e^{ -0.0188*6}\\$=-0.168 ( to three decimal places)$

3 0

3 years ago