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SCORPION-xisa [38]
3 years ago
6

A square measures 17r on each side. Which monomial represents the area of the square?

Mathematics
1 answer:
Eduardwww [97]3 years ago
5 0

Answer:

Area of square = 289r²

Step-by-step explanation:

Given:

Side of square = 17r

Find:

Area of square

Computation:

Area of square = side²

Area of square = (17r)²

Area of square = 289r²

You might be interested in
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
Find the area of the triangle.
ira [324]
Wait is this geometry?
5 0
3 years ago
PLSSS HELP GIVING BRAINLIEST
Vaselesa [24]

Answer:

i think it may be  21.98 but i dunno

Step-by-step explanation:

3 0
3 years ago
What is the area of this compound shape?
Paraphin [41]

Answer:

139.36

Step-by-step explanation:

first you do 8*8 because that would be the area of the square part

8*8=64

then find the area of the semicircle

first the Radis of it is 4 because 8/2=4

A=3.14R^2/2

3.14*4^2/2

3.14*16/2

50.24/2

25.12

now because there are 3 of the semicircles you do

25.12*3

75.36

then you add the 64 from the square to get your answer

75.36+64

139.36

6 0
3 years ago
The question that I'm having issues with is, "The complement of an angle, A, in degrees, is equal to one-sixth of the supplement
dolphi86 [110]
'Complement' = difference between an angle an 90 degrees.

'Supplement' = difference between an angle and 180 degrees.

Complement of A = 90 - A

Supplement of A = 180 - A

The problem says that the complement is 1/6 of the supplement, right ?

So    <u>  90 - A = (1/6) x (180 - A)</u>

Multiply each side of this equation by 6 :

540 - 6 A = 180 - A

Subtract 180 from each side:

360 - 6 A = - A

Add 6A to each side :

360 = 5 A

Divide each side by 5 :

<u>A = 72°</u>
4 0
3 years ago
Read 2 more answers
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