The answer is at the bottom hope this helps
Reference angle and coterminal angle of 5pi 5pi/3 , - 6pi/5
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Answer:
<h2>The slope m = -2</h2>Step-by-step explanation:
The slope-intercept form of an equation of a line:
<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
<em />
We have the equation in the standard form:
Convert to the slope intercept form:
<em>subtract 6x from both sides</em>
<em>divide both sides by 3</em>
slope: <em>m = -2</em>
y-intercept: <em>b = 4</em>
Answer:
0 ≤ Ф ≤ 4π.
Step-by-step explanation:
since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))
the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.
We take
Note that
Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.
The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.