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2 years ago

Milo's steakhouse has 130 tables each table has a dozen roses in the center how many roses are there in all

2 answers:

6 0

130 multiplied by 12 is 1560. So based on that there should be 1560 roses. I'm not 100% sure about this. Hope this helped.

erica [24]2 years ago

3 0

the equation should be 130×12

answer: 1,560

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I need this answered asap please and thankyou :D

suter [353]

Answer:

Step-by-step explanation:

5 0

2 years ago

How many solutions does this linear system have? one solution: (0, 0) one solution: (1, –4) no solution infinite number of solut

Anna35 [415]

The system of equations has infinite solutions.

<h2>Given to us,</h2>

$y=-6x+2$
$-12x-2y=-4$

<h3>Equation 2,</h3>

The value of y is already given in equation 1,

$-12x-2y=-4$

substituting the value of y in equation 2,

$-12x-2(-6x+2)=-4\\-12x +12x-4=-4\\-12x+12x=-4+4\\0=0$

The solution of the two equations is 0. Also, we can see that both the equations are in ratio.

Further, the image also shows that the line of the two equations are coinciding.

Hence, the system of equations has infinite solutions.

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3 0

2 years ago

Write the trigonometric expression sin(sin−1u−tan−1v) as an algebraic expression in u and v. Assume that the variables u and v r

igomit [66]

Answer:

[u – v√(1 – u²)]/√(1 + v²)

Step-by-step explanation:

Let sin^-1(u) = A, therefore sinA = u.

We know that sin(theta) = opposite/hypothenuse

Therefore, sinA = u/1 and u is the opposite side to angle A while 1 is the hypotenuse. Draw an acute triangle placing u opposite to angle A and 1 as the hypotenuse. By Pythagoras theorem the adjacent would be √(1 – u²).

By doing this, it means cosA = adjacent/hypotenuse = √(1 – u²)/1 = √(1 – u²)

Also, let tan^-1(v) = B, therefore tanB = v.

We know that tan(theta) = opposite/adjacent

Therefore, tanB = v/1 and v is the opposite side to angle B while 1 is the adjacent. Draw an acute triangle placing v opposite to angle B and 1 as the adjacent. By Pythagoras theorem the hypothenuse would be √(1 + v²).

Therefore, sinB = opposite/hypotenuse = v/√(1 + v²) and cosB = adjacent/hypotenuse = 1/√(1 + v²)

Now,

sin[sin^–1(u) – tan^–1(v)] =

sin(A – B) =

sinAcosB – sinBcosA =

u[1/√(1 + v²)] – [v/√(1 + v²)][√(1 – u²)] =

[u/√(1 + v²)] – [v√(1 – u²)/√1 + v²)] =

[u – v√(1 – u²)]/√(1 + v²).

8 0

2 years ago

When ∆A′B′C′ is reflected across the line x = -2 to form ∆A″B″C″, vertex (note: please enter your response using apostrophes ins

maria [59]

(A) because it is reflecting over the x-axis.

7 0

3 years ago

The supreme shipping company can load trucks with both rectangular and cylindrical containers. A rectangular container has a vol

soldi70 [24.7K]

the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

The maximum income is $1740

Let x be the number of rectangular containers and y the number of cylindrical containers.

Since a rectangular container has a volume of 100 ft ³and weighs 200 pounds and a cylindrical container has a volume of 200 ft.³ and weighs 100 pounds, and each truck has room for at most 4200 ft.³ of containers and can carry a maximum of 4800 pounds,

We have that the maximum volume of the truck V = 100x + 200y.

Also, the maximum weight of the truck is W = 200x + 100y

Since V = 4200 ft.³ and W = 4800 pounds,

100x + 200y = 4200 and 200x + 100y = 4800

x + 2y = 42 (1) and 2x + y = 48 (2)

Multiplying (1) by 2 and (2) by 1, we have

2x + 4y = 84 (3) and 2x + y = 48 (4)

Subtracting (4) from (3), we have

2x + 4y = 84

2x + y = 48

3y = 36

y = 36/3

y = 12

Substituting y into (1), we have

x + 2y = 42

x + 2(12) = 42

x + 24 = 42

x = 42 - 24

x = 18

Also, since the shipping company charges $60 for a rectangular container and $55 for a cylindrical container, the income, P = 60x + 55y

Since x = 18 and y = 12, the maximum income is P = 60x + 55y

= 60(18) + 55(12)

= 1080 + 660

= $1740

So, the number of rectangular containers to maximze their income is 18 while the number of cylindrical containers to maximize income is 12.

The maximum income is $1740

Learn more about maximum income here:

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3 0

2 years ago