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Nonamiya [84]
4 years ago
13

What is 2 2/3 equivalent to?

Mathematics
1 answer:
son4ous [18]4 years ago
3 0
It’s equivalent to 8/3, also known as 2.66667 (Rounded to fifth decimal place)
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What is 5/7 - 2/3 • 15/14
zimovet [89]
5/7-2/3x 15/14
2/3x15/14=5/7
5/7-5/7=0
0
7 0
3 years ago
HELP FAST ANYONE OLEASE I HAVE LIKE 2 minutes too answer !!
kow [346]

Answer:

C

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
PLZZ HELPP IM FAILLING THIS CLASS
arlik [135]

Answer:

Hope this helps!!! :)

Step-by-step explanation:

#1: if there is buy 1 get 1 free, then buy 6 get 3 free. so 2.8 times 3 = $8.4

#2: 4 for $3. break it up to 1 for $0.75. now 0.75 times 6 = $4.5

#3: the second one. $4.5 < $8.4

#4: 45 times 12 = $54

4 0
3 years ago
Jasmine is baking and selling cupcakes for $15 per dozen.She would like to make more than $120 in cupcake sales. Which number li
pishuonlain [190]

Answer:

Step-by-step explanation:

Jasmine is baking and selling cupcakes for $15 per dozen.

Let x be the number of dozens of cupcake made by Jasmine.

Her total sales= Sales Per Dozen X Number of Dozens of cupcake sold

= $15 X x = $15x

Since she would like to make more than $120 in cupcake sales.

It means her total sales must be greater than $120.

15x>120

x>120/15

x>8

The number line attached represents the solutions to the situation.

All integers to the right of 8 (excluding 8) satisfies the situation.

3 0
3 years ago
In front of a store, there is a row of parking spaces. Cars park parallel to one another, with the front of each car facing the
Gelneren [198K]

The width used for the car spaces are taken as a multiples of the width of

the compact car spaces.

Correct response:

  • The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>

Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.

We have;

Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)

New space design = 16·x + 9×(a·x) = x·(16 + 9·a)

When the dimensions of the initial and new arrangement are equal, we have;

10 + 12·a = 16 + 9·a

12·a - 9·a = 16 - 10 = 6

3·a = 6

a = 6 ÷ 3 = 2

a = 2

Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;

10 + 12·a < 16 + 9·a

Which gives;

x·(10 + 12·a) < x·(16 + 9·a)

Therefore;

The initial total car park space is less than the space required for 16

compact spaces and 9 full size spaces, therefore; the store owners are

incorrect.

Learn more about writing expressions here:

brainly.com/question/551090

5 0
2 years ago
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