3 years ago

1. (3x2)(−2x4) = 3(−2)x2∙4 = 6x8

Mathematics

1 answer:

Molodets [167]3 years ago

8 0

4 . FALSE . i’m not sure about the 3 other ones sorry .

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Find the area : a nonagon with a perimeter of 117 millimeters

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Answer:

Area of nonagon = 1044.6 square millimetres.

Step-by-step explanation:

Let side of the nonagon is a

Given:

The perimeter of nonagon is 117 millimetres

$perimeter=9a$

Put the perimeter value in above equation

$a=\frac{117}{9}$

$a=13$

So the side of the nonagon is 13

The area of the nonagon is .

$A=\frac{9}{4} a^{2} cot(\frac{180}{9})$

where a is side of the nonagon.

Put value of side in above equation

$A=\frac{9}{4} 13^{2} cot(20)$

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$A=\frac{1521}{4}\times 2.747}$

$A=380.25\times 2.747}$

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Therefore, the area of the nonagon is 1044.6 square millimetre.

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Answer:

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Step-by-step explanation:

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