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user100 [1]
3 years ago
7

The rate for mailing an envelope is $0.80 per ounce. Choose a function rule that represents the total cost, c(w), to mail an env

elope weighing w ounces. How much will it cost to mail an envelope that weighs 5 ounces?

Mathematics
1 answer:
galina1969 [7]3 years ago
5 0
The answer is c, the only thing you need to do is multiply the ounces by the cost per ounce
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Please help I’m stuck on this question
mylen [45]

C looks like the smartest answer to go with.

4 0
3 years ago
Read 2 more answers
Which of the following represents the distance between the y-intercept and x-intercept of the line whose equation is y = 3x + 12
Arturiano [62]

Answer:

√160

Step-by-step explanation:

For y-intercept, we use y = mx + c. Comparing both, y = mx +c & y = 3x + 12

y intercept = c = 12

Point is (0, 12)

For x intercept, we use y = m(x - d). We have

y = 3x + 12 → y = 3(x - (-4))

Compare both, x intercept = d = - 4

Point is (-4, 0)

Using distance formula,

Distance = √(0-12)² + (-4-0)² = √12²+4²

Distance = √144+16 = √160

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8 0
3 years ago
How do I do this ??
Nostrana [21]

Answer:

If I'm not mistaking, they want you to find the number in the middle that's between X and Z.

That number would be 3.

Hope this helps a bit! :)

4 0
3 years ago
Read 2 more answers
Using the digits 1 to 9 at most one time each, fill in the boxes to find the largest (or smallest) possible values for x.
Mice21 [21]

Answer:

smallest: 8x -3 = 4; 1y +9 = 2. total = -49/8

 largest: 1x -9 = 8; 2y +3 = 7. total = 19

Step-by-step explanation:

If we use variables to represent the box contents, we can write ...

ax -b = c

dy +e = f

Then the values of x and y are ...

 x = (c +b)/a

 y = (f -e)/d

For positive integer values of the variables, x will always be positive, and y may or may not be negative.

Smallest sum

For the sum to be the smallest, we must have x be as small as possible and the ratio (f-e)/d be as negative as possible.

x will be small for large 'a' and for (c+b) small. For y to be as negative as possible, we want 'd' and 'f' small and 'e' large. Best results are obtained for

8x -3 = 4   ⇒   x = 7/8

1y +9 = 2   ⇒   y = -7

For these coefficients, the sum is -6 1/8 = -49/8.

(note that the values of 'b' and 'c' can be swapped with no net effect)

Largest sum

For the sum to be the largest, we must have x as large as possible: (b+c) large and 'a' small. At the same time we must have y be positive and as large as possible: (f-e) positive and large, 'd' small. Best results are obtained for

1x -9 = 8  ⇒   x = 17

2y +3 = 7   ⇒   y = 2

For these coefficients, the sum is 19. Again, 'b' and 'c' can be swapped with no effect.

_____

Additional comment

These extreme values are verified by examination of the 60,480 possible permutations of the coefficients.

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
VashaNatasha [74]

Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

8 0
3 years ago
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