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konstantin123 [22]
1 year ago
14

If the 4 population assumptions in the hard-weinberg principle are met, what will happen to the allele frequencies?

Mathematics
1 answer:
LekaFEV [45]1 year ago
3 0

The Hardy-Weinberg principle states that the frequency of alleles in a large randomly reproducing population will remain constant from generation to generation if certain assumptions are met.

The assumptions are:

  • No mutations.
  • No migration into or out of the population
  • No selection, and
  • No genetic drift.

<h3>What is the hardy-Weinberg principle?</h3>
  • The Hardy-Weinberg principle, also known as the Hardy-Weinberg equilibrium, model, theorem, or law in population genetics, holds that in the absence of additional evolutionary factors, allele and genotype frequencies in a population would remain constant from generation to generation.

A population is not evolving while it is in Hardy-Weinberg equilibrium. Discover how violations of Hardy-Weinberg assumptions result in evolution.

  • When a population reaches Hardy-Weinberg equilibrium for a gene, it stops evolving and allele frequencies remain constant over generations.
  • Hardy-Weinberg's assumptions include no mutation, random mating, no gene flow, infinite population size, and no selection.
  • If the assumptions for a gene are not met, the population may evolve for that gene (the allele frequencies of the gene may change).

Therefore, the Hardy-Weinberg principle states that the frequency of alleles in a large randomly reproducing population will remain constant from generation to generation if certain assumptions are met.

The assumptions are:

  • No mutations.
  • No migration into or out of the population
  • No selection, and
  • No genetic drift.

Know more about the Hardy-Weinberg principle here:

brainly.com/question/3406634

#SPJ4

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A survey was conducted of 42 students who take math, Eng lish, or history. In the survey, 15 students said they take math and hi
strojnjashka [21]

Answer:

16 students take only English or only Math.

Step-by-step explanation:

We can solve this problem by treating these values as sets, and building the Venn Diagram.

I am going to say that:

A is the number of students who take Math.

B is the number of students who take English.

C is the number of students who take History.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only take Math, A \cap B is the number of students who take both Math and English, A \cap C is the number of students that take both Math and History, and A \cap B \cap C is the number of students that take all these classes.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

There were 42 students suveyed. This means that:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42

We start finding the values from the intersection of three sets.

12 students said they take math, English, and history. This means that:

A \cap B \cap C = 12

18 students said they take English and history. This also takes into account those who take math, english and history. So:

(B \cap C) + (A \cap B \cap C) = 18

B \cap C = 6

17 students said they take math and English.

(A \cap B) + (A \cap B \cap C) = 17

A \cap B = 5

15 students said they take math and history

(A \cap C) + (A \cap B \cap C) = 15

A \cap C = 3

2 students said they only take history.

c = 2

How many students take only English or only math?

This is a + b, that we can find by the following formula:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42

a + b + 2 + 5 + 3 + 6 + 12 = 42

a + b = 16

16 students take only English or only Math.

4 0
3 years ago
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