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3 years ago

15

Albert cuts lawns for neighbors in charges $25 per week. He cuts the lawns for all 15 of his customers every week for 24 weeks d

uring the summer and every other week for 12 weeks during the fall

1 answer:

slava [35]3 years ago

7 0

Is there something else?????

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What is 10/120 in simplest form

Oduvanchick [21]

1/12 is 10/120 is simplest form

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3 years ago

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What is t'(x) when t(x) = In<br> x2<br> 2x2+3x+2<br> ?

Korvikt [17]

Step-by-step explanation:

2-×^2

t(×)=3×

(s o t )(x)=st(×)=s(t(x))=2-(3×)^2=2-9x^2

(s o t)(-7) =2-9(-7)^2=2-9(49)= 2-441= -439

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2 years ago

The slopes of perpendicular line segments are 1/3 and d/5. What is the value of d

a_sh-v [17]

If 2 lines (or line segments) are perpendicular, then the product of their slopes is equal to -1.

Thus, since the given line segments are perpendicular, we have:

$\displaystyle{ \frac{1}{3}\cdot \frac{d}{5}=-1$ .

Multiplying both sides of the equation by 15, we get d=-15.

Answer: d=-15

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2 years ago

Bracket answer to each box to complete the paragraph proof triangle ABC Pro ma equals 66 2/3 on the unit test reasoning and proo

Airida [17]

Answer:

889

Step-by-step explanation:

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2 years ago

Consider the equation: 12x=13-x^212x=13−x 2 12, x, equals, 13, minus, x, squared 1) Rewrite the equation by completing the squar

Flauer [41]

Answer:

$(x + 6)^2 = 49$

$x = 1$ or $x = -13$

Step-by-step explanation:

Given

$12x = 13 - x^2$

Using Completing the Square

$12x = 13 - x^2$ ---- Add $x^2$ to both sides

$x^2 + 12x = 13 - x^2 + x^2$

$x^2 + 12x = 13$

Divide the coefficient of x by 2; then add the square to both sides

$x^2 + 12x + 6^2 = 13 + 6^2$

$x^2 + 12x + 36 = 13 + 36$

$x^2 + 12x + 36 = 49$

Factorize

$x^2 + 6x + 6x + 36 = 49$

$x(x + 6) + 6(x + 6) = 49$

$(x + 6)(x + 6) = 49$

$(x + 6)^2 = 49$

Hence, the equation is $(x + 6)^2 = 49$

Solving further

Take square root of both sides

$(x + 6) = \sqrt{49}$

$x + 6 = \±7$

$x = \±7- 6$

This implies that

$x = 7 - 6$ or $x = -7 -6$

$x = 1$ or $x = -13$

HEnce, the solutions are $x = 1$ or $x = -13$

6 0

2 years ago