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4 years ago

A skateboard travels 55 feet in 4 seconds. Is the skateboard going faster, slower, or the same speed as the scooter?

Mathematics

1 answer:

Assoli18 [71]4 years ago

4 0

Answer:

Slower.

Step-by-step explanation:

I belive it is slower because the scooter was 30 feet per 2 seconds. 30+30+60 feet, 2+2= 4 seconds= 60 feet and 4 seconds which makes the 55 feet per 4 seconds slower.

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A public beach in Florida charges non residents $8 per day for a fishing license and $2.50 per day for live bait. Florida reside

melamori03 [73]

For a non-resident:

$C_{nr}=8d+2.5d=10.5d$

For a resident:

$C_{r}=114+1d$

We want to know the number of days $d$ such that the two costs are equal ie $\{d|C_{nr}(d)=C_{r}(d)\}$

To do this set the two costs equal to each other:

$C_{nr}=C_{r}$

$10.5d=114+1d$

And solve for d:

$10.5d-1d=114+1d-1d$

$9.5d=114$

$d=\frac{114}{9.5}$

$d=12$

The costs will be equal when a resident and a non-resident each use the beach for 12 days.

3 0

4 years ago

Find the measure of ∠3. a. 118 b. 62 c. 31

JulijaS [17]

$answer = 62 \\ solution \\ \: let \: < 3 \: be \: x \\ x + 118 = 180(sum \: of \: angle \: in \: triangle) \\ or \: x = 180 - 118 \\ x = 62 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$

7 0

4 years ago

Read 2 more answers

What is the MAD of 0 0 0 1 3 and 8

IgorLugansk [536]

The Mean Absolute Deviation is - 0 +0+0+1+3+8 = 24/ 6 which would = 4 that's the answer to your question .

Hope that it helps .

7 0

4 years ago

In a class of 18 students, 5 are math majors. A group of four students is chosen at random. (Round your answers to four decimal

ss7ja [257]

Answer:

(a) 0.2721

(b) 0.7279

Step-by-step explanation:

(a) If we choose only one student, the probability of being a math major is $\frac{5}{18}$ (because there are 5 math majors in a class of 18 students). So, the probability of not being a math major is $\frac{18}{18} - \frac{5}{18} = \frac{13}{18}$ (we subtract the math majors of the total of students).

But there are 4 students in the group and we need them all to be not math majors. The probability for each one of not being a math major is $\frac{13}{18}$ and we have to multiply them because it happens all at the same time.

P (no math majors in the group) = $\frac{13}{18} *\frac{13}{18}*\frac{13}{18}*\frac{13}{18} = (\frac{13}{18}) ^4$ = 0.2721

(b) If the group has at least one math major, it has one, two, three or four. That's the complement (exactly the opposite) of having no math majors in the group. That means 1 = P (at least one math major) + P (no math major). We calculated this last probability in (a).

So, P (at least one math major) = 1 - P(no math major) = 1 - 0.2721 = 0.7279

(c) In the group of 4, we need exactly 2 math majors and 2 not math majors. As we saw in (a), the probability of having a math major in the group is 5/18 and having a not math major is $\frac{13}{18}$ . We need two of both, that's $\frac{5}{18}*\frac{5}{18}*\frac{13}{18}*\frac{13}{18}$ . But we also need to multiply this by the combinations of getting 2 of 4, that is given by the binomial coefficient $\binom{4}{2}$ .