Answer:

Step-by-step explanation:
<u>Slope-intercept </u><u>form</u>
y= mx +c, where m is the slope and c is the y-intercept
Line p: y= -8x +6
slope= -8
The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.
m(-8)= -1
m= -1 ÷(-8)
m= ⅛
Substitute m= ⅛ into the equation:
y= ⅛x +c
To find the value of c, substitute a pair of coordinates that the line passes through into the equation.
When x= 2, y= -2,
-2= ⅛(2) +c



Thus, the equation of line q is
.
Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)
Answer:
3643
Step-by-step explanation:
Answer:
30 1/10
Step by step explanation:
71/2-5 2/5= 30 1/10
30 1/10 divided by a (also know as 1) = 30 1/10