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Marianna [84]
3 years ago
15

How much simple interest would you earn on $1,000 if you left it in an account for 9 months? The account pays 3% simple interest

for 1 year. Explain how you found your answer. ​
Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0

Answer:

I=\$22.5

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=\frac{9}{12}\ years  ----> one year is equal to 12 months

P=\$1,000\\r=3\%=3/100=0.03

substitute in the formula above

I=1,000(\frac{9}{12})(0.03)

I=\$22.5

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A person has ​$27000 nvested in stock A and stock B. Stock A currently sells for ​$30 a share and stock B sells for ​$80 a share
Harman [31]

Answer:

Step-by-step explanation:

Let x be initial number of shares of stock A and y be the initial number of shares of stock B.

Since the cost of one share of stock A is $30, the cost of x shares would be $ 30x. Similarly, the cost of y shares of stock B would be $ 80y.

The person bought these x and y shares in $ 27,000. So we can set up the equation as:

30x + 80y = 27000                               Equation 1

Value of stock B triples. So new value of each share of stock B would be $ 240 and the price of y shares will be $ 240y. Value of stock A goes up by 50%. This means the price of each share of stock A would be 30 + 0.5(30) = $ 45 and the price of x shares would be $ 45x.

The worth of stock increased to $ 76,500. So we can set up the equation as:

45x + 240y = 76500                             Equation 2

Multiplying Equation 1 by 1.5 and subtracting from Equation 2, we get:

45x + 240y - 1.5(30x + 80y) = 76500 - 1.5(27000)

45x + 240y - 45x - 120y = 36000

120y = 36000

y = 300

Using the value of y in Equation 1, we get:

30x + 80(300) = 27000

30x = 27000 - 80(300)

30x = 3000

x = 100

This means the person bough 100 shares of stock A and 300 shares of stock B.

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