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lina2011 [118]
2 years ago
6

Mike jogged a total distance of 5 and 1 over 3 miles during the months of october and November. if mike only jogged 1 over 6 mil

e every day, which expression shows the number of days in which he went jogging?
5 and 1/3 times 1/6
5 and 1/3 plus 1/6
5 and 1/3 subtract 1/6
5 and 1/3 divided by 1/6
Mathematics
2 answers:
OleMash [197]2 years ago
5 0
The correct answer for this problem is D: <span>5 and 1/3 divided by 1/6


you can find this by figuring out that Mike has jogged a total of 5 1/3 miles over the course of October and November.  If he only jogged 1/6 miles per day, you would need to find out how many days. 

Adding 1/6 to 5 1/3 miles would mean Mike jogged an additional 1/6 miles.
Subtracting 1/6 from 5 1/3 would mean he jogged 1/6 miles less than 5 1/3 miles. 
Multiplying 5 1/3 and 1/6 means Mike only jogged 1/6 of the total 5 1/3 miles
Dividing 5 1/3 by 1/6 will give you the number of days Mike jogged 1/6 miles</span>
Ksivusya [100]2 years ago
4 0
Mike jogged a total  of A 5 and 1/3 times 1/6
your welcome.
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Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

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f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}

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