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MakcuM [25]
3 years ago
9

The surface area of the figure below is 50.80m^2 True or False

Mathematics
1 answer:
solong [7]3 years ago
8 0

For this case we have that by definition, the surface area of a cone is given by:

SA = \pi * r * s + \pi * r ^ 2

Where:

A: It's the radio

s: It's the slant

Substituting according to the data we have:

SA = \pi * 2.1 * 5.6 + \pi * (2.1) ^ 2\\SA = 36.9264 + 13.8474\\SA = 50.7738 \ m ^ 2

If we round:

SA = 50.8 \ m ^ 2

Answer:

True

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Uranus moves in an elliptical orbit with the sun at one of the foci. The length of the half of the major axis is 2,876,769,540 k
Alina [70]

Answer:

The minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

Step-by-step explanation:

Consider the provided information.

The length of the half of the major axis is 2,876,769,540 kilometers, and the eccentricity is 0.0444.

The eccentricity (e) of an ellipse is the ratio of the distance from the center to the foci (c) and the distance from the center to the vertices (a).

e=\frac{c}{a}

Substitute a = 2,876,769,540 and e = 0.0444 in above formula and solve for c.

0.0444=\frac{c}{2,876,769,540 }

c=127728567.576

Minimum distance of Uranus from the sun is:

a-c=2,876,769,540-127728567.576\\a-c=2749040972.424\approx2749040972

Hence, the minimum distance (perihelion) of Uranus from the sun is 2,749,040,972.

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3 years ago
What is the area of the shaded portion in the square?
Olenka [21]

Answer:

(π/4) - (1/4) square units

Step-by-step explanation:

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