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Colt1911 [192]
3 years ago
12

How do you find e in exponential growth formula?

Mathematics
1 answer:
devlian [24]3 years ago
7 0
You do not have to calculate "e".  This is a mathematical constant similar to "pi" and has a value of 2.718281828459045...
Wikpedia has a good article about it.


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The displacement (in meters) of a particle moving in a straight line is given by the equation of motion
Ksenya-84 [330]

Answer:

  • -2/a³ m/s
  • -2 m/s
  • -1/4 m/s
  • -2/27 m/s

Step-by-step explanation:

The velocity is the derivative of position:

  v = ds/dt = (d/dt)(t^-2) = -2t^-3

For t=a, the velocity is

  -2a^-3 = -2/a³ . . . . meters per second

For t=1, the velocity is ...

  -2·1³ = -2 . . . . meters per second

For t=2, the velocity is ...

  -2·2^-3 = -2/8 = -1/4 . . . . meters per second

For t=3, the velocity is ...

  -2·3^-3 = -2/27 . . . . meters per second

4 0
3 years ago
Patsy by 8 yards of ribbon. She cuts it into 16 equal pieces. How many inches long is each piece?
yanalaym [24]
8 yards divided by 16 is 0.5 yards
8 0
3 years ago
Read 2 more answers
Sandeep has twice as much as sonia. together they have rs 150. how much does sonia have
Inga [223]

let sonia has the (x)

Sandeep would have twice as much as Sonia so (2x)

together they'd have 150.

so, x+2x=150

solve for X

3x=150

X=150/3

So x=50 is what Sonia has,

and Sandeep would have 2(50) =100

5 0
3 years ago
Ms. Federman graded 5 papers in 40 minutes. At this rate, how many minutes will it take her to grade 30 papers?
Ksivusya [100]

Answer:

240 minutes

Step-by-step explanation:

If it's 40 minutes for just 5 papers, we need to figure how many minutes it would take to grade just 1. So you have to divide 40 by 5 which is 8. Then 8 time 30 which is 240.

4 0
3 years ago
Jim’s backyard is rectangular with dimensions of 80 feet by 120 feet. He is planning to designate part of the yard to plant a ve
mariarad [96]
Solution: 5,400 feet^2
Step by step solution:
3/4=0.75
(80*0.75)(120*0.75)
(60)(90)
5400
5,400 feet^2
Hope that helps :)
5 0
2 years ago
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