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2 years ago

Find all y such that the distance between the points (8,10) and (4,y) is 20.

Mathematics

1 answer:

andriy [413]2 years ago

8 0

Answer:

y = 394

Step-by-step explanation:

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Assume that they all agree on the sample size and the sample mean use the pairs below to select the team that has the smallest s

Archy [21]

Step-by-step explanation:

A.Confidence Level: 99.7%; Confidence Interval: 42 to 48

B.Confidence Level: 95%; Confidence Interval: 43 to 47

C.Confidence Level: 68%; Confidence Interval: 44 to 46

D.Confidence Level: 95%; Confidence Interval: 44 to 46

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2 years ago

Look at this cone:<br><br>,,

Assoli18 [71]

Slant height=l=3ft
Radius=r=2ft

We know

$\boxed{\sf \star TSA_{(Cone)}=\pi r(r+\ell)}$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=2 \dfrac{22}{7}\times 2(2+3)$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{44}{7}(5)$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=\dfrac{220}{7}$

$\\ \sf\longmapsto TSA_{(Old\:Cone)}=31.4ft^2$

Now

New slant height =2(3)=6cm
New radius=2(2)=4cm

$\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{22}{7}\times 4(4+6)$

$\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{88}{7}(10)$

$\\ \sf\longmapsto TSA_{(New\:Cone)}=\dfrac{880}{7}$

$\\ \sf\longmapsto TSA_{(New\:Cone)}=125.7cm^2$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{125.7}{31.4}$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cone)}}{TSA_{(Old\:Cone)}}=\dfrac{4}{1}$

$\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cone)}}:{TSA_{(Old\:Cone)}}=4:1}}}$

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3 years ago

100 cm is equal to: 0.1 m 1 m 10 m 1,000 m

riadik2000 [5.3K]

Answer: 1 m or 1 meter

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2 years ago

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How to solve the formula for Vf in the formula of acceleration?

balandron [24]

A = (Vf - Vi)/t
Multiply by t on both sides to clear the denominator
at = Vf - Vi
Add Vi to both sides.
at +Vi = Vf

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3 years ago

I need help with all these questions

Sergio039 [100]

The answer to this question is D and B

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2 years ago