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3 years ago

Graph the equation: x = - 5

Mathematics

1 answer:

Ket [755]3 years ago

8 0

Answer:

Find the graph x = -5 in attached file.

Step-by-step explanation:

Given:

The given equation is $x = -5$

We draw the graph for equation $x = -5$ in attached file.

The graph shows, the given equation is vertical line equation because the value of x is constant for each and every value of y.

Therefore x = -5 is a vertical line equation.

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Complete the table. Use one of the approximate values for T discussed in class (for

gavmur [86]

Answer/Step-by-step Explanation:

Circumference of a circular object = πd

Where,

π = 3.14,

d = diameter

Circumference of hula pop with diameter of 35 in:

Circumference = πd = 3.14*35 = 109.9 in

Diameter of circular pond with a circumference of 556 ft:

556 = 3.14*d

Divide both sides by 3.14

556/3.14 = d

177.07 = d

d ≈ 117 in

Circumference of magnifying glass with a diameter of 5.2 in:

Circumference = πd = 3.14*5.2 = 16.328 ≈ 16.4 cm

Diameter of car tire with a circumference of 71.6 in:

71.6 = 3.14*d

Divide both sides by 3.14

71.6/3.14 = d

22.80 = d

d ≈ 22.8 in

7 0

3 years ago

( 70 POINTS BRAINLIST) an offshore windmill is partly submerged in the ocean. it's tallest point is 120 meters above sea level i

alexdok [17]

Answer:

half of it would be 45

Step-by-step explanation:

120 - 30 = 90

90 divided by 2 = 45

hope this helped! sorry if i didn't answer your question, i was a little bit confused on what you wanted us to solve:)

if u want to find the length of it, it would be 150 because 120 + 30 = 150

7 0

2 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

A school attendance clerk wants to determine if there is a relationship between the number of times a student arrives to school

amid [387]

The correct answer is B because the data points are too scattered

Hope this helped :)

5 0

3 years ago

A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at

icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder, H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from Pythagoras theorem,

B² + P² = H² .

B² + P² = 6² ..............(1) [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

P² = 36 - 1.69

P² = 34.31

P = 5.857

Now,

differentiating (1)

$2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0$

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × $(\frac{dP}{dt})$ = 0

1.14 + 11.38 × $(\frac{dP}{dt})$ = 0

11.38 × $(\frac{dP}{dt})$ = - 1.14

$(\frac{dP}{dt})$ = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

5 0

3 years ago