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3 years ago

Can x-2 be the remainder on division of a polynomial by x+3

Mathematics

1 answer:

Amanda [17]3 years ago

5 0

No because the degree of the reminder must be less than that of the divisor

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Can someone help me find surface area??

natita [175]

Answer:

277cm²

Step-by-step explanation:

Base = 9x8=72

There are 2 triangles with a bottom edge of 9 and a slant height of 13:

1/2(9)(13)=58.5

There are 2 triangles with a bottom edge of 8 and a slant height of 11:

1/2(8)(11)=44

72+58.5+58.5+44+44=277cm²

5 0

3 years ago

What is the image of A(3, 5) under the translation (x - 4, y - 3) ?

azamat

C because (x-4,y-3) = c

4 0

3 years ago

Read 2 more answers

Marie can find the volume of a cube by using the formula V = s³, where s represents the side length of the cube. If Marie's cube

UNO [17]

Answer:

15.625 cm^3

Step-by-step explanation:

$V=2.5^{3} \\V=2.5*2.5*2.5\\V=6.25*2.5\\V=15.625 cm^{3}$

7 0

3 years ago

Pls help me ! L need help here

Sophie [7]

Answer:

H. 40 inches

Step-by-step explanation:

On Wednesday, he is 40 inches taller. ... That would make 5 days of growth, for 100 inches. But this is only 3 days therefore he would grow 40 inches taller

5 0

2 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

7 0

3 years ago