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grin007 [14]
3 years ago
11

Can x-2 be the remainder on division of a polynomial by x+3

Mathematics
1 answer:
Amanda [17]3 years ago
5 0
No because the degree of the reminder must be less than that of the divisor
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Carl is drawing blueprints for a new building. Although the building will be 40 feet (480 inches) tall, his drawing is only 10 i
STatiana [176]

Answer:

48:1

Step-by-step explanation:

In this case we know the actual size and the size in the drawing therefore we can calculate its scale.

What we must do is divide the actual size by the size in the drawing. We know the actual size is 480 inches and in the drawing the size is 10 inches, so:

480/10 = 48

Which means that the relationship between the real and the drawing is 48:1

7 0
4 years ago
Need Help on this ASAP Geometry
navik [9.2K]
You calculate it by taking the change in y's over the change in x's. So (y1-y2)/(x1-x2). You get the equation (-5 - 3)/(5 - 7) which equals 4. 4 is the slope.
7 0
3 years ago
Read 2 more answers
PLEASE!!!
garik1379 [7]
We see on the picture that :
When we go down one row, we add one horizontal and two diagonal cards.

In the first row we have 2 cards
In the second 2+3=5 cards
In the third 5+3=8 cards
etc.

General formula : in the n-th row from the top, we have\boxed{ 2+(n-1)\cdot3\text{ cards}}
5 0
3 years ago
A ball is drawn at random from a box containing 12 red,18
Lubov Fominskaja [6]

<u>Answer:</u>

<u>For a:</u> The probability of getting a red or blue ball is 0.48

<u>For b:</u> The probability of getting a white, blue or orange ball is 0.81

<u>For c:</u> The probability of getting neither white or orange ball is 0.48

<u>Step-by-step explanation:</u>

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}     .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

  • <u>For a:</u>

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48

  • <u>For b:</u>

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81

  • <u>For c:</u>

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

7 0
3 years ago
How do you construct the inscribed and circumscribed circle of a triangle?
suter [353]

Answer:

Draw the triangle.

Draw the perpendicular bisector to each side of the triangle. Draw the lines long enough so that you see a point of intersection of all three lines.

Draw the circle with radius at the intersection point of the bisectors that passes through one of the vertices

6 0
3 years ago
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